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3 years ago

Find the percent of change. Round to the nearest tenth of a percent if necessary. 10 inches to 25 inches. ___ % increase.

Mathematics

1 answer:

andrezito [222]3 years ago

8 0

Answer:

150% change

Step-by-step explanation:

Formula for Percent change = C =[ (new - old)/ old ]* 100%

C = [ (25 in. - 10 in.) / 10 in. ] = [15/10 ] * 100% = 150 %

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In the diagram, AC is a diameter of the circle with center 0. If m ZACB = 50°, what is ZBAC?

Snowcat [4.5K]

Answer:

40degrees

Step-by-step explanation:

Find the diagram attached

Since the triangle ina semi circle is a right angle, hence <B = 90degrees

Also frm the diagram

<A + <B + <C = 180

<A + 90 + 50 = 180

<A + 140 = 180

<A = 180 - 140

<A = 40degrees

Hence the measure if m<BAC is 40degrees

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3 years ago

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Tamara texted a photo of a dolphin to 5 friends. She asked each of her 5 friends to text the photo to 5 more friends. The photo

Andreyy89

So 5
then 5 times 5
then 5 times 5 times 5
so it seems that for x rounds, there will be 5^x

A: 4 rounds so 5^4=625 photos
B. see how many times 5 goes into 78125. the answer is 7 so 7 rounds
C. 1 million=1,000,000 so try big numbers
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3 years ago

How do you solve for #23

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3 years ago

The exact value of cos5pi/12 is:

jonny [76]

Step 1: Convert $\frac{5\pi }{12}$ , which is in radians into degrees. To convert it multiply by $\frac{180}{\pi }$

$\frac{5\pi }{12} =\frac{180}{\pi }$

900/12

Step 2: 75 degrees isn't on the unit circle but 45 degrees and 30 degrees is. Since 45 + 30 = 75 you can use the cosine of 45 and 30 to find the exact value

cos45 = $\frac{\sqrt{2} }{2}$

cos30 = $\frac{\sqrt{3} }{2}$

Step 3: Add the cos45 and cos30 to get cos5pi/12

$\frac{\sqrt{2} }{2} +\frac{\sqrt{3} }{2} = \frac{\sqrt{2}+\sqrt{3}}{2}$

Hope this helped!

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3 years ago

Find the percent of change. Round to the nearest tenth of a percent if necessary. 10 inches to 25 inches. ___ % increase.​

Find the percent of change. Round to the nearest tenth of a percent if necessary. 10 inches to 25 inches. ___ % increase.