Answer:
$7.50 per direct labor hour
Explanation:
Calculation for the predetermined overhead allocation rate
Using this formula
Predetermined overhead allocation rate = Factory overhead/Direct labor hours
Let plug in the formula
Predetermined overhead allocation rate = $1,500,000/200,000 hours
Predetermined overhead allocation rate = $7.50 per direct labor hour
Therefore the predetermined overhead allocation rate is $7.50 per direct labor hour
Answer:
Refer below.
Explanation:
Time-Variant :
Historical data is kept in a data warehouse. For instance, one can recover documents from 3 months, a half year, a year, or even past data from a data warehouse. These varieties with an exchanges framework, where regularly just the most current record is kept.
Subject-Oriented :
A data warehouse focus on the displaying and investigation of data for leaders. In this manner, data warehouses regularly give a compact and clear view around a specific subject, for example, client, item, or deals, rather than the worldwide association's progressing activities. This is finished by barring data that are not valuable concerning the subject and including all data required by the clients to comprehend the subject.
Answer:
A. Ethical Lapse
Explanation:
Ethical lapse is an error in judgement that produces a harmful outcome. An ethical lapse doesn't show a complete lack of integrity, just an oversight or blind spot. When an individual does this, it doesnt mean the person doesn't understand ethics or none his view on the issue has changed. Ethical lapses can be large or small scale, kept private or publicized and be illegal or within the realm of the law, but immoral.
<span>Profit needs to be maximized.
Profit = 30x+45y where x and y are respectively the number of model A and model B fax machines manufactured.
Objective function:
max(30x+45y)
Constraints:
x≥0 ---------------(1)
y≥0 ---------------(2)
x+y ≤ 2500 since the demand is capped at 2500 -----------(3)
100x+150y≤600000 since manufacturing costs cannot exceed $600000-----(4)
Solve the following two equations to identify where the two boundary lines (3) and (4) intersect.
x+y=2500-----(3)
100x+150y=600000---(4)
Multiplying (3) by 100
100x+100y=250000----(5)
(5)-(4)
50y=350000
y=7000
x=-4500
since the constraint states that x≥0, only three vertices are considered viz (0,0), (0,2500),(2500,0).
applying the profit function at each of the three vertices:
(0,0) ----- 30(0)+45(0) = 0
(0,2500) ---- 30(0)+45(2500)=112500
(2500,0) ---- 30(2500)+45(0)=75000
Hence by applying the max function, x=0, y=2500.
i.e. Dont produce any 'a' model machine. Manufacture 2500 units of model 'b' to maximise profit</span>
