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3 years ago

6

On the farm, rather than use money, they exchange animals. The exchanges are as follows: 4 bunnies = 3 chickens, 5 chickens = 2

pigs, 3 pigs = 2 donkeys. How many bunnies would you have to trade for a donkey?

1 answer:

Radda [10]3 years ago

4 0

We have to trade 5 bunnies for a donkey.

Solution:

To calculate how many bunnies could be exchanged for a donkey, we have to multiply the exchange rates of each animal/bird.

One bunny = 3/4 chickens (0.75 chicken),

One chicken = 2/5 pigs (0.4 pigs)

One pig = 2/3 donkeys (0.67 donkeys).

On multiplying all of the above rates we get,

0.75*0.4*0.67=0.2

Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

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Answer:

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Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

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P = Principal amount,

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n = Number of times interest is compounded per year,

t = Time in years.

$6\%=\frac{6}{100}=0.06$

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

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$1000=P(1+0.12)^{3}$

$1000=P(1.12)^{3}$

$1000=P*1.404928$

$\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}$

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Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

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evablogger [386]

Answer:

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Step-by-step explanation:

For this exercise you need to remember one of the properties for exponents.

There is a property called the "Negative property of exponents" which states the following:

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As you can observe, $b^n$ is the reciprocal of $b^{-n}$

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Observe the expression. As you can notice, the base "n" has a negative exponent, which is -6.

Therefore, applying the Negative property of exponents explained at the beginning of this explanation, you can simplify the expression.

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UkoKoshka [18]

Answer:

Husband:

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Woman:

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Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

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$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

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Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

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$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

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$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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Answer:

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Step-by-step explanation:

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