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marshall27 [118]
2 years ago
12

Which is the simplified form of n Superscript negative 6 p cubed?

Mathematics
2 answers:
evablogger [386]2 years ago
3 0

Answer:

Third option. \frac{p^3}{n^{6}}

Step-by-step explanation:

For this exercise you need to remember one of the properties for exponents.

There is a property called the "Negative property of exponents" which states the following:

b^{-n}=\frac{1}{b^n}

Where b \neq0

As you can observe,  b^n is the reciprocal of b^{-n}

In this case you have the following expression given in the exercise:

n^{-6}p^3

Observe the expression. As you can notice, the base "n" has a negative exponent, which is -6.

Therefore, applying the Negative property of exponents explained at the beginning of this explanation, you can simplify the expression.

Then, the simplified form of  n^{-6p^3} is the one shown below:

n^{-6}p^3=\frac{p^3}{n^{6}}

Galina-37 [17]2 years ago
3 0

Answer:

C!

Step-by-step explanation:

it is

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WHAT IS X³-27 SIMPLIFIED
Eduardwww [97]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>(</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>)</u><u>³</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u>(</u><u>3</u><u> </u><u>-</u><u> </u><u>x</u><u>)</u>

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

=  {x}^{3}  -  {3}^{3}

From trinomial expansion:

{(x - y)}^{3}  = (x - y)(x - y)(x - y) \\

open first two brackets to get a quadratic equation:

{(x - y)}^{3}  = ( {x}^{2}  - 2xy +  {y}^{2} )(x - y)

expand further:

{(x - y)}^{3}  =  {x}^{3}   - y {x}^{2}  - 2y {x}^{2}  + 2x {y}^{2}  + x {y}^{2}  -  {y}^{3}  \\  {(x - y)}^{3}  =  {x}^{3}  -  {y}^{3}  + 3x {y}^{2}  - 3y {x}^{2}  \\  {(x - y)}^{3}  =  {x}^{3}  -  {y}^{3}  + 3xy(y - x) \\  \\ { \boxed{( {x}^{3} -  {y}^{3} ) =  {(x - y)}^{3}   - 3xy(y - x)}}

take y to be 3, then substitute:

( {x}^{3}  - 3^3) =  {(x - 3)}^{3}  - 9x(3 - x)

5 0
2 years ago
Show working please!
Nina [5.8K]
You do -2 plus 4. Answer is 2.
Then do 2-(-2) which is 0.
The final answer is 2.
7 0
3 years ago
6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
riadik2000 [5.3K]

Answer:

404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)

44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

13.5 cm²

(using area of ∆ = ½.a.b.sin C for the triangle)

Volume of water = cross-sectional area * length

13.5 * 30 cm³

404 cm³

6 0
1 year ago
Please help this is timed
elena-14-01-66 [18.8K]

Answer:

option d is correct

de=9 and ef=15

6 0
3 years ago
Read 2 more answers
How do you find the HCF of 15t and 6s?
earnstyle [38]

Answer:

HCF=3

Step-by-step explanation:

Factors of 15t= 3*5*t

Factors of 6s= 2*3*s

HCF= Common factors

common factor = 3

HCF=3

4 0
2 years ago
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