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andrew11 [14]
2 years ago
8

A submarie is 671 feet below

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Answer:

Uh I don't really know where the question was in that sentance, but if your trying to convert it to meters the answer is 204.521 meters.

Step-by-step explanation:

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PLEASE HELP ME!!
tatiyna
For
y=ax²+bx+c
the x value of the axis of symmetry is -b/(2a)

so test them

A., -b/(2a)=-(-8)/(2*-2)=8/-4=-2, yep
B. -b/(2a)=-2/(2*1/2)=-2/1=-2, yep
C. -b/(2a)=-(-16)/(2*4)=16/8=2, nope, need -2
D. -b/(2a)=-12/(2*3)=-12/6=-2, yep

answer is C
3 0
2 years ago
What is the error in the equation?
omeli [17]
-54+4=54+4 .......-50+58they are not equal 
5 0
3 years ago
Read 2 more answers
Cho tam giác ABC vuông ở A có AB=12 cm, AC=5cm
tensa zangetsu [6.8K]
English pls coz I don’t understand
7 0
2 years ago
From 1985 to 2007, the number B B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 B(t)=-329.4t+1
Romashka-Z-Leto [24]

Answer:

12100

Step-by-step explanation:

If the number B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 from 1985 to 2007 where t = 0 correspond to year 1985

In order to determine the amount of federally insured banks that were there in 1990, we will first calculate the year range from initial time 1985 till 1990

The amount of time during this period is 5years. Substituting t = 5 into the modeled equation will give;

B ( t ) = − 329.4 t + 13747

B(5) = -329.4(5) + 13747

B(5) = -1647+13747

B(5) = 12100

This shows that there will be 12100 federally insured banks are there in the year 1990.

5 0
3 years ago
Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.
WARRIOR [948]
The polynomial 2x^3 + 5x^2-8x-20 may have solutions which are the divisors of -20, therefore -20 has the following divisors: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.
If x=1, then 2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0,
if x=-1, then 2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0,
if x=2, then 2\cdot2^3 + 5\cdot2^2-8\cdot2-20=0, then x=2 is a solution and you have the first factor (x-2). 
If x=-2, then 2\cdot(-2)^3 + 5\cdot(-2)^2-8\cdot(-2)-20=0, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of 2x^3 + 5x^2-8x-20 , then the polynomial x^2-4 is a divisor of 2x^3 + 5x^2-8x-20 and dividing the polynomial 2x^3 + 5x^2-8x-20 by x^2-4 you obtain 
 2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5).











5 0
2 years ago
Read 2 more answers
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