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tino4ka555 [31]
3 years ago
12

What is r the common ration in the geometic sequence 2, -14, 98, -687

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

r is -7

Step-by-step explanation:

(I believe that you mistyped and meant that the fourth term in the sequence should be -686)

The easiest way to find the common ratio is to divide the numbers that are adjacent to each other

\frac{-14}{2} =-7\\\\\frac{98}{-14} =-7\\\\\frac{-686}{98} =-7

As you can see, when we divide a term by its previous term, we get -7 every time. This is our common ratio.

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Use the Distributive Property to solve the equation.
aliya0001 [1]

Answer:

x = -6

Step-by-step explanation:

-5(x + 3) = 15

Distribute the -5

-5x -15 =15

Add 15 to each side

-5x-15+15 =15+15

-5x = 30

Divide each side by -5

-5x/-5 = 30/-5

x =-6

8 0
3 years ago
For which value of a does Limit of g(x) as x approaches alpha not exist?​
Hunter-Best [27]

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

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7 0
2 years ago
Question is in the picture please explain how you got ur answer!
Alexandra [31]
I believe if I’m not wrong the answer should be B 1/6
5 0
3 years ago
Read 2 more answers
The equation x^2+ (k - 3)x + (3 - 2k) = 0, where k is a constant, has two distinct real roots.
Lisa [10]

Step-by-step explanation:

For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,

b^2 - 4ac must be positive.

b^2 - 4ac > 0

(k - 3)^2 - 4(3 - 2k) > 0

k^2 - 6k + 9 - 12 + 8k > 0

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4 0
2 years ago
Calcular la edades actuales de una madre y sus dos hijos sabiendo que hace 14 años la dad de la madre era 5
rodikova [14]

The present age of mother and her daughter respectively are; 40 and 10 years respectively.

<h3>How to Solve Algebra Word Problems?</h3>

Let x and y be the present age of mother and her daughter respectively.

Therefore;

x + y = 50

x = 50 − y     .....(1)

After 20 years, mother's age will be twice her daughter's age at the time. Thus;

x + 20 = 2(y + 20)

x − 2y = 20     .....(2)

Plugging eq 1 into eq 2 gives us;

50 − y − 2y = 20

3y = 30

y = 10

Thus;

x = 50 − 10

x = 40

Thus, the present age of mother and her daughter is 40 and 10 years respectively.

Translation of the question into English is;

The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.

Read more about Algebra Word Problems at; brainly.com/question/21405634

#SPJ1

6 0
2 years ago
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