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2 years ago

Consider the statements below. Which are propositions? Mark all that apply.

Mathematics

1 answer:

allochka39001 [22]2 years ago

5 0

The following statements are considered to be propositions:

2 + 2 = 7

There are more men than women at BYU-Idaho.

2 + 2 = 4

Ron hates spiders.

<h3>What is deductive reasoning?</h3>

Deductive reasoning can be defined as a type of logical reasoning that typically involves drawing conclusions based on a given set of rules and conditions or from one or more premises (factual statements) that are assumed to be generally (universally) true.

<h3>What is a proposition?</h3>

A proposition can be defined as a type of statement (assertion) that is typically used to express an opinion or a judgement, with either a true or false answer.

This ultimately implies that, a proposition refers to a type of statement (assertion) that is either a true or false.

In this context, we can infer and logically deduce that the following statements are considered to be propositions:

2 + 2 = 7

There are more men than women at BYU-Idaho.

2 + 2 = 4

Ron hates spiders.

Read more on propositions here: brainly.com/question/24158168

#SPJ1

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Chicken Delight claims that 87% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 80 or

jeka57 [31]

Answer:

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

Step-by-step explanation:

In this question we have to test an hypothesis.

The null and alternative hypothesis are:

$H_0: \pi\geq0.87\\\\H_a:\pi$

The significance level is assumed to be 0.01.

The sample of size n=80 gives a proportion of p=61/80=0.7625.

The standard deviation is:

$\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }=\sqrt{\frac{0.87*0.13}{80} }=0.0376$

The statistic z is then

$z=\frac{p-\pi+0.5/N}{\sigma}=\frac{0.7625-0.87+0.5/80}{0.0376} } =\frac{-10125}{0.0376} =-2.70$

The P-value is

$P(z$

The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

6 0

3 years ago

Samuel deposited money in an account that pays an annual simple interest rate of 3.5%. at the end of 5 years, samuel earns $2625

evablogger [386]

He has deposited 1500 dollars into the account.

4 0

3 years ago

Read 2 more answers

What digits makes 3,71? Divisible by 3 (connections academy unit test)

wlad13 [49]

Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Let us check which digits will make 371? divisible by 3.

$3+7+1+0=11$

11 is not divisible by 3.

Now let us check other digits as well.

$3+7+1+1=12$

12 is divisible by 3.

$3+7+1+4=15$

15 is also divisible by 3.

$3+7+1+7=18$

18 is divisible by 3 as well.

Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.

6 0

3 years ago

6.8 * 10(2)<br> *keep in note that "2" is an exponent in this question*

Virty [35]

Answer:

Step-by-step explanation:

6.8 × $10^2$

= 68

5 0

3 years ago

A researcher wants to see if birds that build larger nests lay larger eggs. He selects two random samples of nests: one of small

True [87]

Answer:

95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.

Step-by-step explanation:

Confidence interval is given by mean +/- margin of error (E)

Eggs from small nest

Sample size (n1) = 60

Mean = 37.2

Sample variance = 24.7

Eggs from large nest

Sample size (n2) = 159

Mean = 35.6

Sample variance = 39

Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11

Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93

Difference in mean = 37.2 - 35.6 = 1.6

Degree of freedom = n1+n2 - 2 = 60+159-2 = 217

Confidence level = 95%

Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132

E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79

Lower limit = mean - E = 1.6 - 0.79 = 0.81

Upper limit = mean + E = 1.6 + 0.79 = 2.39

95% confidence interval for the difference in average mass is (0.81, 2.39)

3 0

3 years ago