Answer: 65/100 or simplified
Step-by-step explanation:
The standard form for the equation of a circle is :
(x−h)^2+(y−k)^2=r2 ----------- EQ(1)
where handk are the x and y coordinates of the center of the circle and r is the radius.
The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (7,-4)and(1,-10) is :
((7+(1))/2,(-4+(-10))/2)=(4,-7)
So the point (4,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(7−(4))^2+(-4−(-7))^2=9+9=18
⇒r=√18
Subtituting h=4, k=-7 and r=√18 into EQ(1) gives :
(x-4)^2+(y+7)^2=18
I think your equation is wrong. the domain of f(x)= 5x+2 is ALL REAL NUMBERS. That means it’s negative infinity to positive infinity.
The x-y coordinates for the given equation are: (-2,11),(-1,7),(0,3), (1,-1) and (2,-5).
<h3>Linear Function</h3>
A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:
- a= the slope;
- b=the constant term that represents the y-intercept.
The given equation is 16x + 4y = 12. For solving this question, you should replace the given values of x for finding the values of y.
Thus,
- For x= -2, the value of y will be:
16*(-2)+4y=12
-32+4y=12
4y=12+32
4y=44
y=11
- For x= -1, the value of y will be:
16*(-1)+4y=12
- -16+4y=12
- 4y=12+16
- 4y=28
- y=7
- For x= 0, the value of y will be:
16*(0)+4y=12
- For x= 1, the value of y will be:
16*(1)+4y=12
- 16+4y=12
- 4y=12-16
- 4y=-4
- y= -1
- For x= 2, the value of y will be:
16*(2)+4y=12
- 32+4y=12
- 4y=12-32
- 4y=-20
- y= -5
Read more about the linear equation here:
brainly.com/question/1884491
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