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Pani-rosa [81]
4 years ago
15

2.4 An aircraft travels 1000 m in 4.0 s. What isits speed?​

Physics
1 answer:
padilas [110]4 years ago
5 0

Answer:

\huge{ \boxed{ \tt{250 \:  \sf{m \: / \: s} }}}

Explanation:

\star{ \sf{ \:  \underline{ Given}}} :

\sf{Distance \: travelled \:  = 1000 \: m}

\sf{Time \: taken \:  =  \: 4.0 \: s}

\underline{ \sf{Let's \: find \: it's \: speed}}  :

\boxed{ \sf{Speed =  \frac{Distance \: travelled}{Time \: taken} }}

\mapsto{ \sf{Speed =  \frac{1000 \: m}{4.0 \: s}}}

\mapsto{ \sf{speed  = 250 \: m \:/ \: s}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

x=\frac{v_{i}^{2}sin(2\alpha)}{g} (1)

Donde:

  • v(i) es la velocidad inicial del cañon (82 m/s)
  • α es el ángulo de tiro
  • g es la gravedad (9.81 m/s²)
  • x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

sin(2\alpha)=\frac{xg}{v_{i}^{2}}

sin(2\alpha)=\frac{560*9.81}{82^{2}}

sin(2\alpha)=0.82

\alpha=\frac{sin^{-1}(0.82)}{2}

\alpha=27.39^{\circ}

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

v_{x}=\frac{x}{t}

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

v_{i}cos(\alpha)=\frac{x}{t}

t=\frac{x}{v_{i}cos(\alpha)}

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c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

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For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:

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