A point on the rim of a 0.75 m diameter grinding wheel changes speed uniformly from 11 m/s to 20 m/s in 8.1 s. what is the avera

Question

GalinKa [24]

3 years ago

12

A point on the rim of a 0.75 m diameter grinding wheel changes speed uniformly from 11 m/s to 20 m/s in 8.1 s. what is the avera

ge angular acceleration of the wheel during this interval?

Physics

1 answer:

Lynna [10] · Answer 1 · 2022-02-28T09:37:51+03:00

<span>3.0 sâ»Â˛ We can calculate the tangential acceleration by dividing the change in speed by the elapsed time, e.g. (vâ‚ - vâ‚€) / t = (20 m/s - 11 m/s) / 8.1 s = 1.111 m/sÂ˛ Now we can calculate the angular acceleration by dividing by the radius. The radius of the wheel is half its diameter, so r = 0.75 m / 2 = 0.375 m Finally, the angular acceleration is 1.111 m/sÂ˛ / 0.375m = 3.0 sâ»Â˛ The unit sâ»Â˛ is just an alternate way of writing 1/sÂ˛.</span>