Answer:
0.2 A
Explanation:
Current: This is the rate of flow of charge in a circuit. The S.I unit of charge is Ampere (A).
Note: When resistors are connected in parallel, the total current is equal to the sum of the individual current in each resistor.
It = I1 + I2 + I3......................... Equation 1
Where,
It = Total current, I1 = current in the first resistor, I2 = current in the second resistor, I3 = current in the third resistor.
Given: It = 0.71 A, I1 = 0.27 A, I2 = 0.24 A.
Substitute into equation 1
0.71 = 0.27+0.24+I3
0.71 = 0.51+I3
I3 = 0.2 A.
Hence the current through the third resistor = 0.2 A
Answer:
(E) μs(mA +mB)g
Explanation:
We can apply for mB:
∑ Fx = mB*a (→)
⇒ Ffriction = mB*a ⇒ a = Ffriction / mB = μs*N / mB
⇒ a = μs*(mB*g) / mB ⇒ a = μs*g (acceleration of the system)
Now, for mA we have
∑ Fx = mA*a (→)
F - Ffriction = mA*a ⇒ F = mA*a + Ffriction
⇒ F = mA*(μs*g) + μs*(mB*g) ⇒ F = μs*g*(mA + mB)
We must know that the friction acts only between the two blocks
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