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3 years ago

What is the value of x in the solution to this system of equations?

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer:

Step-by-step explanation:

B) -1

The 'x' value =-1 and y =-7

The solution of the given system of equations

(-1,-7)

Step-by-step explanation:

Step(i)

Given that the system of equations

x-y = 6 ..(i)

y = 2x -5 ..(ii)

By using substitution method,

substitute y=2x-5 in equation (i) , we get

x -(2x-5) =6

x -2x+5 =6

-x = 6-5

-x =1

x=-1

Step(ii):-

Put x=-1 in equation (ii) , we get

y = 2(-1) -5 = -2-5 =-7

The solution of the given system of equations

(-1,-7)

sp2606 [1]3 years ago

3 0

Answer:

B) -1

The 'x' value =-1 and y =-7

The solution of the given system of equations

(-1,-7)

Step-by-step explanation:

Step(i)

Given that the system of equations

x-y = 6 ..(i)

y = 2x -5 ..(ii)

By using substitution method,

substitute y=2x-5 in equation (i) , we get

x -(2x-5) =6

x -2x+5 =6

-x = 6-5

-x =1

x=-1

Step(ii):-

Put x=-1 in equation (ii) , we get

y = 2(-1) -5 = -2-5 =-7

The solution of the given system of equations

(-1,-7)

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3 years ago

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Step-by-step explanation:

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5 0

3 years ago

Find the roots of the equation x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago