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Aleks [24]
3 years ago
7

Dynamic Host Configuration Protocol is the protocol that assigns __________ to devices joining a network.

Computers and Technology
1 answer:
inessss [21]3 years ago
7 0
<h2>Answer:</h2>

Option D: IP addresses

Dynamic Host Configuration Protocol is the protocol that assigns <u>IP addresses</u> to devices joining a network.

<h2>Explanation:</h2>
  • Dynamic host configuration protocol is abbreviated as DHCP.
  • Networks are managed according to DHCP protocol widely.
  • It is used to assign IP address to the devices in a network.
  • While using Static protocol, we are allowed to assign he IP addresses to the connected users ourself from a given range.
  • Where as in DHCP, each device is assigned IP address dynamically from a pool of addresses.
  • DHCP is thus a ast and efficient way of assigning IPs to the devices as it gives each device a unique IP.

<h2>I hope it will help you!</h2>
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  • The graph of the function is attached below.
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Explanation:

Given the function

f\left(x\right)\:=\:5x^2-\:20

As we know that the x-intercept(s) can be obtained by setting the value y=0

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y=\:5x^2-\:20

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5x^2-20=0

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5x^2-20+20=0+20

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Dividing both sides by 5

\frac{5x^2}{5}=\frac{20}{5}

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

so the x-intercepts will be: (2, 0), (-2, 0)

we also know that the y-intercept(s) can obtained by setting the value x=0

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y=\:5(0)^2-\:20

y=0-20

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Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.

The video above uses the example

{

d

y

d

x

=

cos

(

x

)

y

(

0

)

=

−

1

to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you  

y

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(

x

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+

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Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in  

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−

1

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y

=

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x

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Explanation:

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