Which expression represents the probability that a student chooses an art elective and a history elective

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

The sum of two integers is 2. Their difference is 10.

lesantik [10]

The two integers are D. -4 and 6

7 0

3 years ago

Simplify 8(xy + 8) + 1.

kobusy [5.1K]

Look at the picture.

I hope this helps!

5 0

3 years ago

Read 2 more answers

Name the line and plane shown in the figure.

ira [324]

Answer: I think your answer is B, but I'm not positive

Step-by-step explanation:

7 0

4 years ago

There are 7 boxes stacked on the floor in the math department supply closet. Each box has a height of 10 inches or 8 inches. The

Orlov [11]

Answer:

5 of the 7 boxes are 8 inches in height

Step-by-step explanation:

Mathematically;

1 ft = 12 inches

So, 5 ft will measure 5 * 12 = 60 inches

So from what we have ,

We want to combine 8 and 10 inches to give 60 inches total

Let the number of 10 inches be x and the number of 8 inches be y

Mathematically;

x + y = 7 •••••(i)

10x + 8y = 60 ••••(ii)

From equation i, x = 7-y

Put this in equation ii

10(7-y) + 8y = 60

70-10y + 8y = 60

70-60 = 10y-8y

2y = 10

y = 10/2

y = 5

5 0

3 years ago