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3 years ago

Someone please help me, I’m begging! I will brainliest and everything!! 20 (points) too

Mathematics

1 answer:

Vadim26 [7]3 years ago

6 0

Answer:

I dont think its accepted

Step-by-step explanation:

because 2 out of 3 groups had majority of the people opposing the proposal so I say that it's not accepted.

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4# is a two digit number ,where # represents the digit at ones place . 7999 ÷ 4# lies between ---------

Hitman42 [59]

Answer:

$7999 \div 4\#$ lies between 163.245 and 199.975

Step-by-step explanation:

Given

2 digit = 4#

Required

The range of $7999 \div 4\#$

Let

$\# = 0$ --- the smallest possible value of #

So:

$7999 \div 40 = 199.975$

Let

$\# = 9$ --- the largest possible value of #

So:

$7999 \div 49 = 163.245$

<em>Hence, </em> $7999 \div 4\#$ <em> lies between 163.245 and 199.975</em>

4 0

3 years ago

A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia

Sindrei [870]

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

$d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m$

So, the required distance is equal to 73 m.

5 0

3 years ago

X^2y^4/z^3 / x^3z^2/y

Likurg_2 [28]

Answer: y3/xz

Step by step is provided in the screenshot below

6 0

3 years ago

Erika calculated that she would spend $115 on school supplies this year. She actually spent $82.50 on school supplies. What is E

DerKrebs [107]

The equation to find percent error is:
percent error=(experimental-theoretical)/theoretical *100
So, (115-82.5)/82.5=0.393939*100
39.3939%, or 39.94%

Hope this helps!!

6 0

3 years ago

Read 2 more answers

Simplify the expression 2√ 20 − 3√ 7 − 2√ 5 + 4√ 63 .

earnstyle [38]

Answer:

The simplified form is,

$\boxed{\boxed{6\sqrt{5}+9\sqrt{7}}}$

Step-by-step explanation:

The given expression is,

$=2\sqrt{20}-3\sqrt{7}+2\sqrt{5}+4\sqrt{63}$

$=2\sqrt{4\times 5}-3\sqrt{7}+2\sqrt{5}+4\sqrt{9\times 7}$

$=2(\sqrt{4}\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(\sqrt{9}\times \sqrt{7})$

$=2(2\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(3\times \sqrt{7})$

$=4\sqrt{5}-3\sqrt{7}+2\sqrt{5}+12\sqrt{7}$

$=4\sqrt{5}+2\sqrt{5}+12\sqrt{7}-3\sqrt{7}$

$=6\sqrt{5}+9\sqrt{7}$

8 0

4 years ago

Read 2 more answers