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3 years ago

14

Find the area of figure ABCDE if angles A, B, and C are right triangle

1 answer:

Levart [38]3 years ago

6 0

Answer:

<em>85 ft</em><em>.</em>

Step-by-step explanation:

8*10=80 (the value of the the rectangle by itself)

then we take the values we are given and find the width and height of the triangle. Knowing it is a right triangle, we perform two equations,

15-10 (the total length of the polygon) 5 ft

and

8-6 (to find the height of the triangle, using the length where the hypotenuse of the triangle cuts off the rectangle) 2 ft

With this, we now have the length and width of the right triangle, and multiply them together to get 10. Because that formula only works on rectangles and squares, but we know that the triangle is a right triangle, we divide the 10 in half to get 5, which is the area of the triangle. Together, the value of the area for the rectangle and the triangle together result in 85 ft (remember to label units when in a written test!)

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Find the y intercepts of 3x^2+24x-51. quadratic formula

julia-pushkina [17]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, starting with the y-intercept. To find the y-intercept, set the x variable to zero and solve as such:

$y=3*0^2+24*0-51\\y=0+0-51\\y=-51$

<u>Your y-intercept is (0,-51).</u>

Next, using our equation plug the appropriate values into the quadratic formula:

$x=\frac{-24\pm \sqrt{24^2-4*3*(-54)}}{2*3}$

Next, solve the multiplications and exponent:

$x=\frac{-24\pm \sqrt{576-(-648)}}{6}\\\\x=\frac{-24\pm \sqrt{576+648}}{6}$

Next, solve the addition:

$x=\frac{-24\pm \sqrt{1224}}{6}$

Now, simplify the radical using the product rule of radicals as such:

Product Rule of Radicals: √ab = √a × √b

√1224 = √12 × √102 = √2 × √6 × √6 × √17 = 6 × √2 × √17 = 6√34

$x=\frac{-24\pm 6\sqrt{34}}{6}$

Next, divide:

$x=-4\pm \sqrt{34}$

<u>The exact values of your x-intercepts are (-4 + √34, 0) and (-4 - √34, 0).</u>

Now to find the approximate values, solve this twice: once with the + symbol and once with the - symbol:

$x=-4+ \sqrt{34},-4- \sqrt{34}\\x\approx 1.83, -9.83$

<u>The approximate values of your x-intercepts (rounded to the hundredths) are (1.83,0) and (-9.83,0).</u>

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3 years ago

What 1,045 to the nearest thousands

faltersainse [42]

1,045 to the nearest thousands would be <u>1,000</u> because you must round down since there are no numbers close enough to round up.

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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2 years ago

What is the name of the figure?

Serhud [2]

That is a Triangular Prism.

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3 years ago

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Solve the quadratic equation below for the exact values of x.<br><br> 4x² - 5 = 75

vfiekz [6]

Answer:

x = ±2√5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Terms/Coefficients
Multiple Roots

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

4x² - 5 = 75

<u>Step 2: Solve for </u><em><u>x</u></em>

[Addition Property of Equality] Add 5 on both sides: 4x² = 80
[Division Property of Equality] Divide 4 on both sides: x² = 20
[Equality Property] Square root both sides: x = ±2√5

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3 years ago

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