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antoniya [11.8K]
4 years ago
15

15x+100=82 (has pic)

Mathematics
2 answers:
aksik [14]4 years ago
5 0
15x+100=28
x=-6/5
The answer is -6/5
klemol [59]4 years ago
5 0
Subtract 100 from both sides making it 15x= -18 then divide both sides by 15 making it x= -1.2
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Vincent's pie recipe calls for 5 ounces of pecans and 7 ounces of walnuts. How many total ounces of nuts does his recipe call fo
sergij07 [2.7K]

Answer:

12 nuts

Step-by-step explanation:

7 + 5 = 12

4 0
3 years ago
Can someone help me ASAP plzz
Shtirlitz [24]
IM PRRETTY SURE ITS D BEB
4 0
3 years ago
10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sampl
Alex17521 [72]

Here is the full question:

The \  shell \   of  \ the \  land  \ snail \  Limocolaria  \ martensiana  \ has \  two  \ possible  \ colorforms:  \ streaked  \ and  \ pallid.  \ In  \  a \ certain \  population  \ of  \ these   \ snails,  \ 60\%  \ o f  \ theindividuals \  have  \ streaked  \ s hells.\ 16  \ Suppose  \ that  \ a  \ random \ sample  \ of \  10  \ snailsis \  to  \ be \ chosen  \ from  \ this \  population.  \ F ind  \ the  \ probabilit y \  that  \ the  \ percentage  \ of

streaked-shelled  \ snails   \ in  \ t he  \ sample \  will  \ be

(a) 50\%. \  (b) 60\%.  \ (c) 70\%.

Answer:

(a) 0.2007

(b) 0.2510

(c) 0.2150

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

X \sim Binom (n =1 0, p = 0.60)

The Probability mass function (X) is:

P(X =x)= (^n_x) p^x(1-p)^{n-x}; x = 0,1,2,3...

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ = \sqrt{np(1-p)}

= \sqrt{10*0.6*(1-0.6)}

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

a)

P(X = 0.5) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_5 * (0.6)^5(1-0.6)^{10-5}

= \dfrac{10!}{5!(10-5)!} * (0.6)^5(1-0.6)^{10-5}

= 0.2007

b)

P(X = 0.6) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_6 * (0.6)^6(1-0.6)^{10-6}

= \dfrac{10!}{6!(10-6)!} * (0.6)^6(1-0.6)^{10-6}

= 0.2510

c)

P(X = 0.7) = ^nC_x p^x (1 -p) ^{(n-x)}

= ^{10}^C_7 * (0.6)^7(1-0.6)^{10-7}

= \dfrac{10!}{7!(10-7)!} * (0.6)^7(1-0.6)^{10-7}

= 0.2150

7 0
3 years ago
Erik Buys 2.5 pounds of cashews. If each pound of cashews cost $7.70, how much will he pay for the cashews?
Colt1911 [192]

Answer:

$19.25

Step-by-step explanation:

$7.70 x 2.5 = $19.25

brainliest please ;)

5 0
3 years ago
18. A sum of money was shared among
Vesna [10]

Answer is something I’m not sure of

8 0
4 years ago
Read 2 more answers
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