Answer:
d = (3 i + 5 j) 3 [m] x-distance and 5 [m] y-distance
Explanation:
We can find the displacement if we use a diagram with the cartesian coordinates of the displacement of the mouse.
In the attached image we can see each of the vectors and the origin where the mouse was in the initial position and then the final position after the mouse moved to the right.
So the mouse moved 3 meters to the right and 5 meter upward.
Answer:
v₂ = 1.8 [m/s]
Explanation:
To be able to solve this problem we must raise the principle of conservation and quantity of movement. It is going to study the momentum before and after the firing of the rifle.
P = m*v
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Now we need to analyze the moment before and after the shot.
where:
m₁ = mass of the rifle = 5 [kg]
v₁ = velocity of the rifle and the bullet before firing = 0 (no movement)
m₂ = mass of the bullet = 15 [g] = 0.015 [kg]
v₂ = velocity of recoil [m/s]
v₃ = velocity of the bullet after firing = 600 [m/s]
Now replacing:
Answer:
The bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Explanation:
Given;
density of liquid, ρ = 1400 kg/m³
frequency of the wave, f = 390 Hz
wavelength, λ = 7.60 m
The speed of the sound is given by;
v = fλ
v = 390 x 7.6
v = 2964 m/s
The bulk modulus of the liquid is given by;
where;
B is bulk modulus
B = (1400)(2964)²
B = 1.229 x 10¹⁰ N/m²
B = 1.229 x 10¹⁰ Pa
Therefore, the bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Answer:
The change of the volume of the device during this cooling is
Explanation:
Given that,
Mass of oxygen = 10 g
Pressure = 20 kPa
Initial temperature = 110°C
Final temperature = 0°C
We need to calculate the change of the volume of the device during this cooling
Using formula of change volume
Put the value into the formula
Hence, The change of the volume of the device during this cooling is