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3 years ago

11

To pop a balloon you stab it with a pencil. If the area of the pencil tip is .01 cm² and the pressure applied by the pencil to t

he balloon is 100 N/ cm², how hard (what force) must you push on the pencil to make the balloon pop?

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

Push with force of 1N

Explanation:

I have explained in the paper.

Goodluck

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A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on

aliya0001 [1]

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

F = ma

solve for a

a = $\frac{F}{m}$

Substitution

$a = \frac{100}{400}$

Simplification and result

a = 0.25 m/s²

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Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the ap

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Answer:

The answer is " $1.144 \times 10^{-4} \ m$ ".

Explanation:

$w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\$

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An astronaut has a mass of 90 kg. The astronaut travels to Mars, where gravity is weaker. The acceleration of free fall on the s

marin [14]

Answer:

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2 years ago

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An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel

Licemer1 [7]

Answer:

$v=4.44\frac{m}{s}$

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero) and accelerates at a constant rate, position can be described like this: $x=v_{0}t +\frac{1}{2} at^{2}$ where x is the position, t is the time a is the acceleration and $v_{0}$ is initial velocity. In this way acceleration can be found. $a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }$ .

Now we are able to found velocity at any time with the formula: $v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}$

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3 years ago

according to newtons first law of motion, what will an object in motion do when no external force acts on it?

shutvik [7]

Answer:

The object will not move.

Explanation:

If nothing pushes against it it will not move. If its not on a slant it will not move.

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