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4 years ago

A mouse climbs 5m directly up a tree and then 3m to the right on a tree limb. What are the

Physics

1 answer:

BigorU [14]4 years ago

7 0

Answer:

d = (3 i + 5 j) 3 [m] x-distance and 5 [m] y-distance

Explanation:

We can find the displacement if we use a diagram with the cartesian coordinates of the displacement of the mouse.

In the attached image we can see each of the vectors and the origin where the mouse was in the initial position and then the final position after the mouse moved to the right.

So the mouse moved 3 meters to the right and 5 meter upward.

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A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 31.8°, the block starts

galina1969 [7]

Answer:

$\mu_s = 0.62$

$\mu_k = 0.415$

The motion of the block is downwards with acceleration 1.7 m/s^2.

Explanation:

First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.

$x - x_0 = v_0t + \frac{1}{2}at^2\\3.4 = 0 + \frac{1}{2}a(2)^2\\a = 1.7~m/s^2$

Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.

$F = ma\\F = 1.7m$

Now, let’s investigate the free-body diagram of the block.

Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,

$F = mg\sin(\theta) - \mu_k mg\cos(\theta)\\1.7m = mg\sin(31.8) - \mu_k mg\cos(31.8)\\1.7 = (9.8)\sin(\theta) - mu_k(9.8)\cos(\theta)\\mu_k = 0.415$

As for the static friction, we will consider the angle 31.8, but just before the block starts the move.

$mg\sin(31.8) = \mu_s mg\cos(31.8)\\\mu_s = tan(31.8) = 0.62$

5 0

3 years ago

How do you solve e from the equation f=e/s

Andrej [43]

1738 Fetty wap bhsyfnd hdnchd hand hdnzudnusjd jdnshdkdndb hdkcnd

7 0

4 years ago

For life to flourish on Earth, several changes occurred that affected the atmosphere, such as _____.

e-lub [12.9K]

Evolution of cyanobacteria that produce O2volcanic outgassing to create a thicker atmosphereformation of an ozone layer to block harmful radiationall of the above<span>only a and c

Are the options</span>

8 0

3 years ago

A spelunker is surveying a cave. She follows a passage 140 m straight west, then 290 m in a direction 45? east of south, and the

zimovet [89]

Answer:

Magnitude of fourth displacement is approximately 95 metres,

Direction of fourth displacement is straight west.

3 0

4 years ago

A 5.31 kg object is swung in a vertical circular path on a string 2.99 m long. The acceleration of gravity is 9.8 m/s 2 . If the

11111nata11111 [884]

Answer:

T = 120.3 N

Explanation:

Since, the tension in the rope is acting against both the centripetal force and the weight of the stone. As both act downward towards center of the circle and tension acts towards point of support that is upward. So, tension will be equal to the sum of centripetal force and weight of the stone:

Tension = Centripetal Force + Weight of Stone

T = mv²/r + mg

where,

m = mass of stone = 5.31 kg

r = radius of circle = length of string = 2.99 m

g = 9.8 m/s²

Therefore,

T = (5.31 kg)(6.2 m/s)²/(2.99 m) + (5.31 kg)(9.8 m/s²)

T = 68.27 N + 52.03 N

4 0

3 years ago