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larisa86 [58]
3 years ago
10

Suma a trei numere este 130. Stiind ca ele sunt invers proportionale cu numerele 2,3,4 aflati numerele

Mathematics
2 answers:
Dominik [7]3 years ago
8 0
6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30, hope that helps!!
garik1379 [7]3 years ago
6 0
A+b+c=130 a,b,c  ip  cu 2,3,4 2a=3b=4c=k a=k/2 b=k/3 c=k/4 k/2 + k/3+ k/4= 130  aducem la acelasi numitor (12) 6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30
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Step-by-step explanation:

We will learn how to solve proportion problems. We know, the first term (1st) and the fourth term (4th) of a proportion are called extreme terms or extremes, and the second term (2nd) and the third term (3rd) are called middle terms or means.

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example

1. Check whether the two ratios form a proportion or not:

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