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3 years ago

Suma a trei numere este 130. Stiind ca ele sunt invers proportionale cu numerele 2,3,4 aflati numerele

Mathematics

2 answers:

Dominik [7]3 years ago

8 0

6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30, hope that helps!!

garik1379 [7]3 years ago

6 0

A+b+c=130 a,b,c ip cu 2,3,4 2a=3b=4c=k a=k/2 b=k/3 c=k/4 k/2 + k/3+ k/4= 130 aducem la acelasi numitor (12) 6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30

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2 years ago

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3 years ago

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3 years ago

[Quick Answer Needed] Which of the following shows the extraneous solution to the logarithmic equation?

Nitella [24]

Answer:

Step-by-step explanation:

Given the logarithmic equation

$\log_4x+\log_4(x-3)=\log_4(-7x+21)$

First, notice that

$x>0\\ \\x-3>0\Rightarrow x>3\\ \\-7x+21>0\Rightarrow 7x$

So, there is no possible solutions, all possible solutions will be extraneous.

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$\log_4x+\log_4(x-3)=\log_4x(x-3),$

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$\log_4x(x-3)=\log_4(-7x+21)\\ \\x(x-3)=-7x+21\\ \\x^2-3x+7x-21=0\\ \\x^2+4x-21=0\\ \\D=4^2-4\cdot 1\cdot (-21)=16+84=100\\ \\x_{1,2}=\dfrac{-4\pm 10}{2}=-7,\ 3$

Hence, $x=3$ and $x=-7$ are extraneous solutions

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2 years ago