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Galina-37 [17]
2 years ago
7

the ratio of boys to girls in a chorus is 5:6. which shows an equivalent ratio. Use a proportion to solve. A 10 boys to 12 girls

B 15 boys to 19 girls C 20 boys to 25 girls or D 24 boys to 28 girls
Mathematics
1 answer:
iVinArrow [24]2 years ago
8 0
A. 10 boys to 12 girls because both numbers in the given ratio have been multiplied by two 5*2=10 6*2=12. None of the other options can be simplified to the original given ratio of 5:6.
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PLS HELP ME ASAP FOR 8 (SHOW WORK!)
lys-0071 [83]
11 won                              x   
__________                _____
18 total games                162 games per season 
muliply 11*162 =1782
then divide 1782/18
X=99 
8 0
3 years ago
A bathtub can hold 80 gallons of water. The faucet flows at a rate of 4 gallons per minute. What percentage of the tub will be f
krok68 [10]

Answer:

120

Step-by-step explanation:

80 divided by 2 is 40 plus 80 would be 120 which is 6 minutes worth of filling

6 0
2 years ago
when asked to write a point slope equation for a line passing through the points (-3,-5) and (2,4) a student wrote y-4=-9/5(x-2)
Eduardwww [97]
(-3,-5)(2,4)
slope(m) = (4 - (-5) / (2 - (-3) = (4 + 5) / (2 + 3) = 9/5

y - y1 = m(x - x1)
slope(m) = 9/5
(2,4)...x1 = 2 and y1 = 4
sub
y - 4 = 9/5(x - 1)....this is the correct answer

the student figured the slope wrong....it is 9/5...not -9/5
5 0
3 years ago
\\\\\\\-------!!!!!40 POINTS!!!!-----\\\\\\\\\
aleksandrvk [35]
Let's actually find the line of best fit...

m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)

m=(11*836-130*55)/(11*385-3025)

m=2046/1210  

m=93/55

b=(Σy-93Σx/55)/n

b=(55Σy-93Σx)/(55n)

b=(7150-5115)/(55*11)

b=185/55, so the line of best fit is:

y=(93x+185)/55

A)  The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.

Which means that those who do not practice at all will win about 3.36 times

B) y(13)=(93x+185)/55

y(13)≈25.34

So after 13 months of practice one would expect to win about 25.34 times.
3 0
3 years ago
From 1960 to 2010, a certain money stock measure was growing at the rate of approximately 43e(1/2)x billion dollars per decade,
natulia [17]

Answer:

1222 billion dollars.

Step-by-step explanation:

To find the total increase from 1960 to 2010, we need to find the growth of each decade and sum them all:

In the period 1960-1970, we have x = 1, and the growth is:

y(1) = 43e(1/2) = 70.895

In the period 1970-1980, we have x = 2, and the growth is:

y(2) = 43e(2/2) = 116.8861

The growth in the following 3 periods are:

y(3) = 43e(3/2) =192.7126

y(4) = 43e(4/2) = 317.7294

y(5) = 43e(5/2) =523.8472

So the total growth in the period 1960 - 2010 is:

Total = y(1) + y(2) + y(3) + y(4) + y(5)

Total = 70.895 + 116.8861+192.726+317.7294+523.8472

Total = 1222.08\ billion\ dollars

Rounding to the nearest billion dollars, we have a total of 1222 billion dollars.

6 0
2 years ago
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