The answer is: 45 * 10 ⁻¹¹ .
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Explanation:
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Given: (9 * 10⁻⁵) * (5 *10 ⁻⁶) ; Simplify.
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(9 * 10⁻⁵) * (5 *10⁻⁶) =
9 * 5 * 10⁻⁵ * 10⁻⁶ =
(9 * 5) * 10⁻⁵ * 10⁻⁶
45 * 10⁻⁵ * 10⁻⁶ ;
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Note the following property of exponents:
xᵃ * xᵇ = x⁽ᵃ⁺ᵇ⁾ ;
As such, 10⁻⁵ * 10⁻⁶ = 10⁽⁻⁵ ⁺ ⁻⁶) = 10 ⁻¹¹ ;
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So; 45 * 10⁻⁵ * 10⁻⁶
= 45 * 10⁻¹¹ .
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Answer:
concave pentagon I'm thinking
Answer:
158.76 cm²
Step-by-step explanation:
Quadrilateral ABCD is composed of 2 right triangles
Construct the line BD, then
Δ ABD and Δ BCD are the 2 right triangles.
The area (A) of a triangle is calculated using
A = 
bh ( b is the base and h the perpendicular height )
Δ ABD with b = 18 and h = 7.5
A = × 18 × 7.5 = 9 × 7.5 = 67.5 cm²
Δ BCD with b = 15.6 and h = 11.7
A = × 15.6 × 11.7 = 7.8 × 11.7 = 91.26 cm²
Thus
area of ABCD = 67.5 + 91.26 = 158.76 cm²
Answer:
Is there supposed to be a graph somewhere?
The dimensions of the smaller box are half those of the larger box. This means that:
*Length of smaller box= length of larger box/2= 24/2= 12cm.
*height of smaller box= height of larger box/2= 30/2= 15cm.
*width of smaller box= width of larger box/2= 10/2= 5cm.
