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AlekseyPX
4 years ago
7

The following table shows the number of snow days each school district in Mill County had last winter. School District District

200200200 District 211211211 District 221221221 District 231231231 District 241241241 Number of snow days 666 888 333 222 666 Find the mean absolute deviation (MAD) of the data set. snow days
Mathematics
2 answers:
lianna [129]4 years ago
4 0

District 221221221. I'm not really sure cause last days of snow each school district some of the school tallied

Ray Of Light [21]4 years ago
3 0

Answer:

District 221221221. I'm not really sure cause last days of snow each school district some of the school tallied

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Vera is an ecologist who studies the change in the bear population of Siberia over time. The relationship between the elapsed ti
rewona [7]

Answer:

  • <em>Every year, the bear population</em><u><em>    shrinks    </em></u><em>by a factor of</em><u><em>    2/3   </em></u>.

Explanation:

The concrete question and the function or data were omitted.

I found the complete question on the internet. Please, find attached the picture with the complete question

You must complete the  sentence about the yearly rate of change of the bear population, telling whether it grows or shrinks and by what factor.

Thus, the goal is to interpret the rate of change in an exponential model.

The exponential model is:

       N(t)=2187\cdot \bigg(\dfrac{2}{3}\bigg)^t

Let's analyze that function.

When t = 0, (2/3)⁰ = 1 and N(0) = 2,187 × 1 = 2,187

Thus, the population of bears starts with 2,187 individuals.

For t = 1, the population will be N(1) = 2,187 × (2/3).

For t = 2, the population will be N(2) = 2,187 × (2/3)²

And so on, every year the population of bears is multiplied by a factor of 2/3.

Since, 2/3 is less than 1, every year the population will be decreasing (decaying), by a factor of 2/3.

Thus, the answer, i.e. the complete sentence, is:

Every year, the bear population<u><em>    shrinks    </em></u>by a factor of<u><em>    2/3   </em></u>.

6 0
3 years ago
Read 2 more answers
I need help plz!!?!???!?
Ksivusya [100]

Answer:

Solution → (3, -1)

Step-by-step explanation:

We ave to identify the graph representing the system of lines first.

y = \frac{2}{3}x-3

Y-intercept of the line = -3

y = -2x + 5

y-intercept of the line = 5

From the given graphs 3rd (extreme right) graph is representing the system of equations.

Solution of the system of equations will be the point of intersection of these lines.

Solution of the system → (3, -1)

8 0
3 years ago
you recently purchased an item the cost $84.99 before tax. the tax on the item was $7.22. what was the tax rate?
lapo4ka [179]
Is approximately 8.49 percent
6 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
(x,5), (-3,6); slope = -1
anyanavicka [17]

Answer:

what exactly is the question to the problem ? it looks like it's already solved ? are you suppose to find something or ?

5 0
3 years ago
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