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Andreyy89
3 years ago
9

Linear Functions 7g+3g-10+3=43 Step by step solution? Thankss!❤️

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0
7g + 3g - 10 + 3 = 43

(first combine likes terms)

10g - 7 = 43

(then add 7 to both sides)

10g - 7 = 43
        +7    +7

10g = 50

(then divide by 10 to get what g is equal to)

10g = 50
/10     /10

g = 5
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C- 29.25

Step-by-step explanation:

This answer goes into the thousendths place, meaning this is the most accurate.

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3 years ago
If m<BEG = (19x + 3)° and m<EGC = (m<GCB + 4x)°, which of the following statements is true about quadrilateral BEGC? Se
viktelen [127]

Answer:

The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only

Step-by-step explanation:

* Lets revise some facts about the quadrilateral

- Quadrilateral is a polygon of 4 sides

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- The sum of measures of the exterior angles of any quadrilateral is 360°

* Lets solve the problem

- DEGC is a quadrilateral

∵ m∠BEG = (19x + 3)°

∵ m∠EGC = (m∠GCB + 4x)°

∵ The sum of the measures of its interior angles is 360°

∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360

∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms

∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides

∴ 23x + 2m∠GCB + m∠CBE = 375

∵ The sum of measures of the exterior angles of any quadrilateral is 360°

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3 0
3 years ago
Help asap idek what to do
daser333 [38]

So to solve this question, your goal is to find out how the way it is solved is not correct.

Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is

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3 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
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