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Verizon [17]
2 years ago
9

Write the decimal number 8.85 as a fraction​

Mathematics
2 answers:
vaieri [72.5K]2 years ago
7 0

Answer:

177/20

Step-by-step explanation:

slamgirl [31]2 years ago
6 0

The correct answer is 8 17/20

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How to do 1.36 divided by 0.08 I’n a house formation
xz_007 [3.2K]

Answer:

1.36 divided by 0.08 = 17

Step-by-step explanation:

8 0
2 years ago
I really need help!!! It would mean a lot if someone could help me.
Rudiy27

The y answers would be 11, 8, 5, 2, -1.

To find these parts of the table, we simply put the x value in for x and solve for y. The first two are done for you below.

WHEN x = -2

y = -3x + 5

y = -3(-2) + 5

y = 6 + 5

y = 11

WHEN x = -1

y = -3x + 5

y = -3(-1) + 5

y = 3 + 5

y = 8

4 0
3 years ago
Read 2 more answers
Lena spent $39 on fruit at the grocery store. She spent a total of $60 at the store. What percentage of the total did she spend
Likurg_2 [28]

Answer:

The answer is 65%

Step-by-step explanation: Divide 60 by 39 and multiply by 100. So it will look like 39/60=0.65*100=65%. I hope this helps. :)

7 0
3 years ago
3=-1.5n<br><br> pls help me (Solving Equations using Multiplication or Division)
motikmotik

Answer:

n = -2

Step-by-step explanation:

Step 1: Write equation

3 = -1.5n

Step 2: Divide both sides by -1.5

n = -2

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

3 = -1.5(-2)

3 = 3

7 0
3 years ago
Read 2 more answers
An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
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