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GuDViN [60]
2 years ago
11

Is the order pair (3,-4) a solution of the system of linear equations x+y=1 and -6x-3y=-3

Mathematics
1 answer:
4vir4ik [10]2 years ago
7 0

↝ A single coordinate point must make both equations true in order for the point to be a solution.

Substitute x = 3 and y = -4 in both equations.

3-4=1\\-1=1

The equation isn't true. Therefore, this isn't the solution for the system.

-6(3)-3(-4)=-3\\-18+12=-3\\-6=-3

The equation isn't true for this one.

Conclusion ↝ The (3,-4) isn't the solution.

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Answer:

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Step-by-step explanation:

To solve this, you first need to isolate p.

First add 6 on both sides of the equation:

-6 + |2p+3| >7\\\\(+6) -6 + |2p+3| >7 +6\\\\2p + 3 > 13

Then subtract 3 from both sides of the equation.

2p+3-3>13-3\\\\2p > 10\\

The divide both sides by 2.

\dfrac{2p}{2}>\dfrac{10}{2}\\\\p>5

Another solution is possible because of the absolute value.

If |2p+3|>13

Then |2p+3|

<em>Thus we can solve the second solution:</em>

|2p+3|

2p+3

Isolate P again by subtracting both sides by 3

2p+3-3

2p

Then divide both sides by 2:

\dfrac{2p}{2}

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