Answer:
Part a) The rule of the sequence is 
Part b) The height of the ball will be 
Step-by-step explanation:
Part a) Write a rule for the sequence using centimeters. The initial height is given by the term n = 1.
we know that
In a <u>Geometric Sequence</u> each term is found by multiplying the previous term by a constant called the common ratio (r)
In this problem we have a geometric sequence
Let
n-----> the number of path
a1 ----> is the initial height
r -----> the common ratio
we have
The rule for the sequence is equal to
substitute
Part b) What height will the ball be at the top of the third path?
For n=3
substitute in the equation
Answer:
7088 m²
Step-by-step explanation:
The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...
A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²
The area of the bottom part of the box is the sum of its lateral area and its base area.
lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²
base area = lw = (0.8 m)(0.6 m) = 0.48 m²
The total area is then ...
total area = half-cylinder area + lateral area + base area
= 1.0362 m² +2.1 m² +0.48 m²
= 3.6162 m²
__
The area for 1960 mailboxes will be 1960 times this area, or ...
area for week's production = 1960 × 3.6162 m² = 7087.752 m²
It will take about 7088 square meters of aluminum to make these mailboxes.
Cº b<span>. </span>Points<span> on the </span>x<span>-axis ( </span>Y. 0)-7<span> (6 </span>2C<span>) are mapped to </span>points<span>. --IN- on the </span>y<span>-axis. ... </span>Describe<span> the transformation: 'Reflect A ALT if A(-5,-1), L(-</span>3,-2), T(-3,2<span>) by the </span>rule<span> (</span>x<span>, </span>y) → (x<span> + </span>3<span>, </span>y<span> + </span>2<span>), then reflect over the </span>y-axis, (x,-1) → (−x,−y<span>). A </span>C-2. L (<span>0.0 tº CD + ... </span>translation<span> of (</span>x,y) → (x–4,y-3)? and moves from (3,-6) to (6,3<span>), by how.</span>
