The first figure below shows the graph for problem 5).
The second figure below shows the graph for problem 6).
Answer: b
Explanation: A and C are wrong because a negative times a positive is a negative
And D is wrong because a positive times a positive is a positive
Answer:
a) No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.
b) Yes.
- Let event 1 be flipping a coin and event 2 be rolling a die.
- Let event 1 be rolling a die and event 2 be flipping a coin.
The likelihood that any outcome will occur will not change, as the events are independent.
c) see attached
d) 12 outcomes (H = head, T = tail, numbers represent the value of the die)
H 1 T 1
H 2 T 2
H 3 T 3
H 4 T 4
H 5 T 5
H 6 T 6
e)
![\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}](https://tex.z-dn.net/?f=%5Csf%20Probability%5C%3Aof%5C%3Aan%5C%3Aevent%5C%3Aoccurring%20%3D%20%5Cdfrac%7BNumber%5C%3Aof%5C%3Aways%5C%3Ait%5C%3Acan%5C%3Aoccur%7D%7BTotal%5C%3Anumber%5C%3Aof%5C%3Apossible%5C%3Aoutcomes%7D)
![\implies \sf P(even)=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20P%28even%29%3D%5Cdfrac%7B1%7D%7B6%7D%2B%5Cdfrac%7B1%7D%7B6%7D%2B%5Cdfrac%7B1%7D%7B6%7D%3D%5Cdfrac%7B3%7D%7B6%7D%3D%5Cdfrac%7B1%7D%7B2%7D)
![\implies \sf P(head)=\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20P%28head%29%3D%5Cdfrac%7B1%7D%7B2%7D)
![\implies \sf P(even)\:and\:P(head)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20P%28even%29%5C%3Aand%5C%3AP%28head%29%3D%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B2%7D%3D%5Cdfrac%7B1%7D%7B4%7D)
Answer:
m<FGN=(7x+18)º=88º
Step-by-step explanation:
(7x+18)º=(6x-10)º+38º
x=10
so
m<FGN=(7x+18)º=88º
hope this is the answer you're looking for.
Answer:
(
n
−
5
)
(
2
n
+
9
)
Step-by-step explanation:
Factor by grouping