Question

The flavor of anise is due to anethole, a compound with the molecular forumal C10H12O. Combustion of one mole of anethole produces 5541 kJ of thermal energy. If 0.950 g of anethole is combusted in a bomb calorimeter whose heat capacity (Ccalorimeter) is 7.854 kJ/°C, what is the change in temperature of the calorimeter?

Answer 1

Answer:

Change in temperature of calorimeter is $4.52^{0}\textrm{C}$

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.950 g of anethole = $\frac{0.950}{148.2}moles$ of anethole = 0.00641 moles of anethole

1 mol of anethole releases 5541 kJ of heat upon combustion

So, 0.00641 moles of anethole release $(5541\times 0.00641)kJ$ of heat or 35.52 kJ of heat

7.854 kJ of heat increases $1^{0}\textrm{C}$ temperature of calorimeter.

So, 35.52 kJ of heat increases $(\frac{1}{7.854}\times 35.52)^{0}\textrm{C}$ or $4.52^{0}\textrm{C}$ temperature of calorimeter

So, change in temperature of calorimeter is $4.52^{0}\textrm{C}$