Answer: The equation is f(x) =
;
The piece of plastic has to have 10mm of thickness.
Step-by-step explanation: It is known that with 1 mm of thickness, 5% of the intensity is reduced. So, 95% of the light is transmitted.
For each milimetre added, "more" 95% of light is transmitted.
For example, if another milimetre of plastic is added, another 0.95 of light is transmitted:
0.95.0.95 = 0.9025 of light reach the visor
So, the model that relate thickness of plastic and intensity of light is:
f(x) = 
in which:
f(x) is the intensity of light;
x is thickness in mm;
Using the equation, the thickness necessary to reduce intensity to 60% is:
f(x) = 
0.6 = 
log 0.6 = log 
x. log (0.95) = log (0.6)
x = 
x = 9.95
x ≈ 10
The thickness necessary to reduce intensity of light to 60% is 10mm.
Answer:
They let you know the number of numbers there are/will be.
Step-by-step explanation:
Mono, being one, means there will only be one number is the equation.
Bi, being two, means there will be two numbers in the equation.
and tri, being three, means there are three numbers in the equation.
Answer:

Step-by-step explanation:
Look at the picture.
ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

We have

Substitute:
<em>cross multiply</em>


For x use the Pythagorean theorem:

(5•4)-8 the answer is 12 because 5 times 4 is 20. Then 20 minus 8 is 12.
Answer:
384, 216, 290, 192, 384
1446, 1 roll
Step-by-step explanation:
For rectangular boxes, calculate the sum of each side, then multiply it by two.
Box 1: 2(18 x 5) + 2(18 x 4) + 2(5 x 4) = 364
Box 3: 2(11 x 8) + 2(8 x 3) + 2(3 x 11) = 290
Box 5 is a cube (all sides equal), so you can find 1 side's area and multiply it by 6.
Box 5: 6(8 x 8) = 384
For triangular boxes, calculate the edges, then find the triangular area using area = 0.5(base x height).
Box 2: (15 x 3) + (9 x 3) + (12 x 3) + 2(0.5)(9 x 12) = 216
Box 4: 2(13 x 2) + (10 x 2) + 2(0.5)(10 x 12) = 192
Total: 364 + 290 + 384 + 216 + 192 = 1446
Rolls of wrapping paper:
Area of 1 roll = 30 x 60 = 1800
Since 1446 is less than 1800, you only need 1 roll of wrapping paper.