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grin007 [14]
3 years ago
15

In 1983, a can of house paint cost $16.35. In 2000, a can of house paint cost $28.94, and in 2005, a can of house paint cost $32

.54. What is the difference in CPI between 2000 and 2005? a. 12 b. 22 c. 45 d. 77
Mathematics
2 answers:
Vlada [557]3 years ago
6 0

Answer:

22

Step-by-step explanation:

Andrews [41]3 years ago
4 0

Answer:

Option B is correct.

Step-by-step explanation:

CPI stands for Consumer Price index and is used to find the inflation.

The formula used to find CPI is

CPI = (Price of baskets of goods in one year/ Price of baskets of goods in base year) * 100

Here the base year is the starting year, in our case it is 1983 and price of can of paint is $16.35

So, CPI in 2000

Using the above formula and putting the values

CPI in 2000 = (28.94 / 16.35) * 100

CPI in 2000 = 177

CPI in 2005

Using the above formula and putting the values

CPI in 2005 = (32.54 / 16.35) * 100

CPI in 2005 = 199

Difference in CPI between 2000 and 2005 = CPI in 2005  - CPI in 2000

Difference in CPI between 2000 and 2005 = 199 - 177

Difference in CPI between 2000 and 2005 = 22

So, Option B is correct.

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6 0
3 years ago
A business has two loans totaling $50,000. One loan has a rate of 8% and the other has a rate of 12%. This year, the business ex
Debora [2.8K]

Answer:

the 8% loan has a principal of $37500

the 12% loan has a principal of $12500

Step-by-step explanation:

Let's start by writing the general  equation for the interest hwre I is the interest, P is the principal (in our case would be loan amounts), "r" is the interest rate in decimal form (in our case one would be 0.12, and the other one 0.08), and t is the time in years (in our case 1 year).

I=P*r*t

Then we write the interest equation coming from each loan at the end of this year (we call I1 the interest coming from the 12% loan and I2 the interest coming from the 8% one). Since we don't know the loan amounts (in fact those are what we need to find) we will name one "x" and the other "y":

I=P*r*t\\I1=x * 0.12*1\\I2=y*0.08*1

Next, we add these last two equations term by term, and replace the addition of both interests by $4500 as given in the information:

I1=x * 0.12*1\\I2=y*0.08*1\\I1+I2 = 0.12x+0.08y\\4500=0.12x+0.08y

This is our first equation in the variables x and y which are our unknowns.

Now we generate the second equation on x and y by writing in agebraic terms the other piece of information we have: "the total of the two loans is $50000. That is the addition of the principals x and y should equal $50000:

x+y=50000

We solve for y in this last equation and replace its form in terms of x in the equation of the interest, and solve for the unknown x:

y=50000-x\\4500 = 0.12x +0.08 y\\4500=0.12x+0.08(50000-x)\\4500=0.12x+4000-0.08x\\4500=0.12x-0.08x+4000\\4500=0.04x+4000\\4500-4000=0.04x\\500=0.04x\\x=\frac{500}{0.04} =12500

Therefore the amount of the loan at 12% is $12500

Now to find the amount of the second loan "y" we use the equation for the totals of the loans:

x+y=50000\\12500+y=50000\\y=50000-12500=37500

Therefore, the loan at 8% is $37500

5 0
3 years ago
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