Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job
We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)
We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability
P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate
Convert this to a percentage to get roughly 36.67% and this rounds to 37%
Final Answer: 37%
Answer:
1. is not
2. increase
3. remain the same
Step-by-step explanation:
I think it's B. 168 units
Because I multiplied them all together and halved the answer
I think your answer would be A?
Answer:
1) not possible 2)f(x)=-2y+2 3)4
Step-by-step explanation:
2x-3=2x-16
