Coach Smith is buying equipment for his soccer team. He has 11 players and each player needs three uniforms, two shin guards, one ball, and two pairs of cleats.
Part A: Write an algebraic expression to represent this situation.
Part B: If each uniform costs $48.00, each shin guard costs $5.00, each ball costs $17.00, and each pair of cleats costs $89.00, determine how much Coach Smith will spend, before taxes, on equipment for his soccer team.
PART A:
Let the cost of a uniform be a, that of a shin guard, b, that of a ball, c, and that of a pair of cleats, d, then
The algebraic expression representing the situation is given by
11(3a + 2b + c + 2d)
PART B:
The amount coach smith will spend is given by
11(3(48) + 2(5) + 17 + 2(89)) = 11(144 + 10 + 17 + 178) = 11(349) = $3,839
It’s 27 I’m pretty sure
Because 18 divided by 2 gives you 9, then you would add the 9 onto the 18
I’m just asking what time you are doing something else I want so you know how I want it so much better and I’m sorry but answer: 128,000
Answer:
umm
Step-by-step explanation:
The maximum number of pounds p is 224
Step-by-step explanation:
Let
p ----> the maximum number of pounds he can pull without going over the weight limit
we know that
121 pound of rock in the wheelbarrow plus p pounds must be at most 345 pounds
In this problem the word "at most" means "less than or equal to"
so
The inequality that represent this situation is
solve for p
subtract 121 both sides
therefore
The maximum number of pounds is 224
Answer:
The graph shows that the population of deer increases over time.
Step-by-step explanation:
i got it correct.