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3 years ago

Show how to make addend the next tens number

Mathematics

1 answer:

ella [17]3 years ago

8 0

5+5=10, 5+6=11, 5+7=12,etc.

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The difference between h and 9 divided by 3.

Nadusha1986 [10]

Answer:

Step-by-step explanation:

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3 years ago

What is the measurement of x in the equation. 8x+5x+2x-11+6=180

34kurt

Answer:

x = 37/3 = 12.333

Step-by-step explanation:

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

15x - 185 = 5 • (3x - 37)

Equation at the end of step 1 :

Step 2 :

Equations which are never true :

2.1 Solve : 5 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2 Solve : 3x-37 = 0

Add 37 to both sides of the equation :

3x = 37

Divide both sides of the equation by 3:

x = 37/3 = 12.333

4 0

3 years ago

Please help this was due yesterday!

CaHeK987 [17]

Answer:

a) <

b) <

c) >

d) <

e) >

Step-by-step explanation:

5 0

3 years ago

Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0

solmaris [256]

$\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 = \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 = -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}$

5 0

3 years ago

Please help me please

ella [17]

Answer:

-4??

Step-by-step explanation:

4 0

2 years ago