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3 years ago

Complete the recursive formula of the arithmetic sequence -3,-1,1,3

Mathematics

1 answer:

VikaD [51]3 years ago

4 0

Step-by-step explanation:

$- 3 + 11 - 3 = 8$

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Divide (9r-55r+49)/(r-5)

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3 years ago

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yaroslaw [1]

Answer:

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Step-by-step explanation:

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3 years ago

Randy chose B as the correct answer.How did he get that answer?

Simora [160]

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3 years ago

A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe

qaws [65]

The projectile's horizontal and vertical positions at time $t$ are given by

$x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t$

$y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2$

where $g=9.8\dfrac{\rm m}{\mathrm s^2}$ . Solve $y=0$ for the time $t$ it takes for the projectile to reach the ground:

$30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s$

In this time, the projectile will have traveled horizontally a distance of

$x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m$

The projectile's horizontal and vertical velocities are given by

$v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ$

$v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt$

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about $\sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}$ .

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3 years ago

Find tan of 45 degrees

Arturiano [62]

Answer:

tan(45°) = 1

Step-by-step explanation:

We know that sin (45°) = √2/2, and cos(45°) = √2/2.

Given that tan(x) = sen(x) / cos(x), we get:

tan(45°) = (√2/2) / (√2/2) = 1

Therefore, tan(45°) = 1

Attached you will find the important angles summary

6 0

3 years ago