Simplify 3-7 x 5 + 2 x 4

Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

olganol [36]

The answer is 1/2. The reasoning is 1/2 x 1/2=1/4 1/4 x 1/2=1/8 fractions multiply on numerator and denominator then simplify

8 0

3 years ago

Read 2 more answers

The dimension of a mural pointed on the wall of a school is 10 ft by 22 ft. the art club wants to paint a new mural that is x fe

Westkost [7]

Answer:

18 ft and 30 ft

Step-by-step explanation:

The new dimensions will be:

10 + x and 22 + x

The area is 540

Using area equation we get:

(10 + x)(22 + x) = 540
x² + 32x + 220 = 540
x² + 32x = 320
x² + 2x*16 + 256 = 320 + 256
(x + 16)² = 576
x + 16 = √576 (Ignoring the negative root as the length is never negative)
x + 16 = 24
x = 8

The new dimensions are:

10 + 8 = 18 ft and
22 + 8 = 30 ft

6 0

2 years ago

The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

$(6,112,50), (11,206.25)$

$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

3 years ago

Si mi disco duro tiene una capacidad de 1.5 Terabytes ¿ cuántas llaves de 32 Gigabits caben en ese disco duro?

Art [367]

Answer:

The number of 32 Gigabit keys that can be fitted on the hard drive is 375.

Step-by-step explanation:

The question is:

If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?

Solution:

1 Terabyte = 8000 Gigabits

Then 1.5 Terabytes in Gigabits is:

1.5 Terabytes = (8000 × 1.5) Gigabits

= 12000 Gigabits

One key is of 32 Gigabits.

Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

$\text{Number of 32 Gigabit keys}=\frac{12000}{32}=375$

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.

4 0

3 years ago

van someone please help me with this i dont need an explaination i just need a. b. c. or d. please and thank you

Talja [164]

Answer:

option C

$f(x)=-\sqrt{x+3}+8$

Step-by-step explanation:

we have

$f(x)=-2\sqrt{x-3}+8$

using a graphing tool

see the attached figure N $1$

The range is the interval--------> (-∞,8]

$y\leq 8$

case A) $f(x)=\sqrt{x-3}-8$

using a graphing tool

The range is the interval--------> [-8,∞)

$y\geq -8$

case B) $f(x)=\sqrt{x-3}+8$

using a graphing tool

The range is the interval--------> [8,∞)

$y\geq 8$

case C) $f(x)=-\sqrt{x+3}+8$

using a graphing tool

The range is the interval--------> (-∞,8]

$y\leq 8$

case D) $f(x)=-\sqrt{x-3}-8$

using a graphing tool

The range is the interval--------> (-∞,-8]

$y\leq -8$

5 0

3 years ago