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levacccp [35]
2 years ago
14

A store sells 6 oranges for $3 what is the cost for 10 oranges ?

Mathematics
2 answers:
stealth61 [152]2 years ago
7 0

Answer:

5

Step-by-step explanation:

3÷6 =0.50 this means every orange costs 50 cents .50 x2 = 1 so you have 2 oranges at the cost of one dollar, 2x5 =10 oranges 1x5=5 dollars

-BARSIC- [3]2 years ago
6 0
$5 for 10 oranges. Would be $1 dollar for every 2 oranges
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The graph shows the calling charges of two cell phone companies. At how many minutes do the two companies charge the same amount
vaieri [72.5K]

Answer:

the correct answer would be c. 20 minuets

Step-by-step explanation:


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2 years ago
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You drive 140 miles in 2.5 hours and 300 miles in 5.5 hours. What is the rate of change ?
Sveta_85 [38]
The answer is one and five elevenths, or: 1 5/11

this is because 140/2.5 is 56 and 300/5.5 is 54 6/11.

56 - 54 6/11= 1 5/11
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3 years ago
1) Marcos deseja comprar uma guitarra. Seu amigo possui um e quer vender a vista por R$850,00. Caso Marcos prefira, pode parcela
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
3 years ago
Calculate the perimeter of this figure<br>to the nearest tenth.​
natima [27]

Answer:

41ft is the perimeter

Step-by-step explanation:

7 0
3 years ago
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