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Naily [24]
3 years ago
15

Factorise 400x^2-49y^2

Mathematics
2 answers:
sattari [20]3 years ago
6 0

Answer:

(20x - 7y)(20x + 7y).

Step-by-step explanation:

This is the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b). So:

400x^2-49y^2

= (20x - 7y)(20x + 7y).

bazaltina [42]3 years ago
3 0

Answer:

(20x + 7y) (20x - 7y)

Step-by-step explanation:

400x²-49y² = (20x + 7y) (20x - 7y)

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2 years ago
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3 years ago
a square garden has a diagonal of 12 m. What is the perimeter of the garden? Express in simplest radical form
lianna [129]

Answer:

The perimeter of the garden, in meters, is 24\sqrt{2}

Step-by-step explanation:

Diagonal of a square:

The diagonal of a square is found applying the Pythagorean Theorem.

The diagonal of the square is the hypothenuse, while we have two sides.

Diagonal of 12m:

This means that d = 12, side s. So

s^2 + s^2 = 12^2

2s^2 = 144

s^2 = \frac{144}{2}

s^2 = 72

s = \sqrt{72}

Factoring 72:

Factoring 72 into prime factors, we have that:

72|2

36|2

18|2

9|3

3|3

1

So

72 = 2^{3}*3^{2}

So, in simplest radical form:

s = \sqrt{72} = \sqrt{2^{3}*3^{2}} = \sqrt{2^3}*\sqrt{3^2} = 2\sqrt{2}*3 = 6\sqrt{2}

Perimeter of the garden:

The perimeter of a square with side of s units is given by:

P = 4s

In this question, since s = 6\sqrt{2}

P = 4s = 4*6\sqrt{2} = 24\sqrt{2}

The perimeter of the garden, in meters, is 24\sqrt{2}

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3 years ago
Can someone please help me with this <br> 4(x-10)-6(x-4)
bagirrra123 [75]

Answer:

16

Step-by-step explanation:

4 x 10 = 40

6 x 4 = 24

40 - 24 = 16

7 0
3 years ago
Read 2 more answers
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