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Leona [35]
3 years ago
11

Why solve this alone. When you can't use a phone?

Mathematics
2 answers:
lord [1]3 years ago
7 0

Answer:

12

Step-by-step explanation:

Evgen [1.6K]3 years ago
5 0

Answer:

For the first one the answer is 12

Step-by-step explanation:

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Solve the equation 6(y+1.5)= -18. what is the value of y? y=
asambeis [7]

Answer:

y = -4.5

Step-by-step explanation:

6 0
3 years ago
50 POINTS EACH
Andrews [41]

Since s and t are complimentary, that means ∠s + ∠t = 90

From the picture, we also know that ∠t + ∠LGM = 90

Set them equal to each other:

∠s + ∠t = ∠t + ∠LGM, solve:

∠s = ∠LGM

Now using the fact that tangent = opposite/adjacent:

tan (∠s) = \frac{y}{h}

tan (∠s) = \frac{h}{x}

Set them equal to each other to get:

\frac{y}{h} = \frac{h}{x}

Solve:

h^{2}= xy\\h = \sqrt{xy}

Part B:

Using tan (∠s) = \frac{y}{h}

We get: h = \frac{3}{tan38} = 3.84 meters

Hope that helps!

3 0
3 years ago
Jabari is power washing houses for a summer job. For every job, he charges an initial fee plus $30 for each hour of work. His to
guapka [62]

Answer: f=30t+50


Step-by-step explanation:

Given: Jabari's total fee, f, for a single job is a function of the number, t, of hours it takes him to complete the job.

For every job, he charges an initial fee plus $30 for each hour of work.

let m be his initial fee.

Then f=30t+m.......(1)

Also, his total fee for a 4-hour job, for instance, is $170.

Put t=4 and f=170 in (1), we get

170=30(4)+m\\\Rightarrow170=120=m\\\Rightarrow\ m=170-120\\\Rightarrow\ m=50

Now, put m=50 in the (1), we get the function's formula for Jabari's total fee, f as

f=30t+50


3 0
3 years ago
Is the first and second right?
Flura [38]
The first one is. the second is 'prime'
6 0
4 years ago
Read 2 more answers
Apel Sinoman has 100 ft of fencing material to enclose a rectangular exercise run for her dog. One side of the run will border h
Olegator [25]

Answer:

For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

Step-by-step explanation:

Let the length of the rectangular exercise run = l ft

and width of the run = w ft

Sinoman has to cover a rectangular exercise run from three sides with the fencing material,

So length of the material = (l + 2w) ft

l + 2w = 100

l = 100 - 2w --------(1)

Area of the rectangular area covered = Length × width

A = lw

A = w(100 - 2w)    [(l = 100 - 2w)from equation (1)

For maximum area we find the derivative of area and equate it to zero.

\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]

A'=\frac{d}{dw}(100w-2w^{2} )

A' = 100 - 4w

For A' = 0

100 - 4w = 0

4w = 100

w = 25 ft

From equation (1)

l = 100 - 2w

l = 100 - 2×(25)

l = 50 ft

Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

5 0
4 years ago
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