Answer:
y = -4.5
Step-by-step explanation:
Since s and t are complimentary, that means ∠s + ∠t = 90
From the picture, we also know that ∠t + ∠LGM = 90
Set them equal to each other:
∠s + ∠t = ∠t + ∠LGM, solve:
∠s = ∠LGM
Now using the fact that tangent = opposite/adjacent:
tan (∠s) = 
tan (∠s) = 
Set them equal to each other to get:
= 
Solve:

Part B:
Using tan (∠s) = 
We get:
meters
Hope that helps!
Answer: 
Step-by-step explanation:
Given: Jabari's total fee, f, for a single job is a function of the number, t, of hours it takes him to complete the job.
For every job, he charges an initial fee plus $30 for each hour of work.
let m be his initial fee.
Then
.......(1)
Also, his total fee for a 4-hour job, for instance, is $170.
Put t=4 and f=170 in (1), we get

Now, put m=50 in the (1), we get the function's formula for Jabari's total fee, f as

The first one is. the second is 'prime'
Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)

A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.