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tamaranim1 [39]
3 years ago
12

A rectangle has a length at most two more than seven times the width. If the perimeter is less than or equal to 52 units, find t

he lest possible width and length.
Mathematics
1 answer:
ella [17]3 years ago
7 0

7x + 2 \leqslant 52
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939miles * 15gallons / 40miles = x
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Step-by-step explanation:

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Solve for x.Question options:A) 11 B) 13 C) 12 D) 10
babymother [125]

Line YZ is the midsegment of triangle QRS because it connects the midpoints of lines QR and RS. We would solve for x by appying the midsegment theorem which states that the midsegment is half the length of the third side or base. This means that

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7 0
1 year ago
3. Solve the equation. (1 point)<br> 5x – 5 = 3x -9<br> 0-1<br> O-3<br> 0-2
Crazy boy [7]

Answer:

x = 2

Step-by-step explanation:

Solve for x:

5 x - 5 = 3 x - 9

Subtract 3 x from both sides:

(5 x - 3 x) - 5 = (3 x - 3 x) - 9

5 x - 3 x = 2 x:

2 x - 5 = (3 x - 3 x) - 9

3 x - 3 x = 0:

2 x - 5 = -9

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2 x + (5 - 5) = 5 - 9

5 - 5 = 0:

2 x = 5 - 9

5 - 9 = -4:

2 x = -4

Divide both sides of 2 x = -4 by 2:

(2 x)/2 = (-4)/2

2/2 = 1:

x = (-4)/2

The gcd of -4 and 2 is 2, so (-4)/2 = (2 (-2))/(2×1) = 2/2×-2 = -2:

Answer:  x = -2

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3 years ago
Find the value of b if it is known that the graph of y=−3x+b goes through point: N(5, 2)
Fittoniya [83]

Into the equation y=−3x+b substitute 5 for x and 2 for y, obtaining:

2 = -3(5) + b.  Then 2 = -15 + b, or b = 17.

5 0
3 years ago
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