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2 years ago

A rectangle has a length at most two more than seven times the width. If the perimeter is less than or equal to 52 units, find t

he lest possible width and length.

Mathematics

1 answer:

ella [17]2 years ago

7 0

$7x + 2 \leqslant 52$

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2 years ago

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3 years ago

Multiply or divide as indicated. x 2 • x 5

WARRIOR [948]

Hi there!

${x}^{2} \times {x}^{5} = x {}^{2 + 5} = {x}^{7}$

We can also write is out entirely.
${x}^{2} = x \times x$
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6 0

3 years ago

Pick the correct answer Please help thanks :)

meriva

Answer:

Step-by-step explanation:

First create the equation that has slope of -1 in the form of y=mx+b. Because the slope is -1, m=-1, so the equation is y=-x+b. Now we see that we are given the point (-3, 8) as an intersection point. Substitute x and y for -3 and 8 in our equation. With this information, our equation becomes 8=3+b. Solving, b=5. Our equation is now y=-x+5.

Simplifying all of the answer choices, we have

A. y=-x-5

B. y=-x+5

C. y=-x-5

D. and E. as what they already show

The only answer that matches is B.

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1 year ago