Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Answer:
42.415
Step-by-step explanation:
if its buy one get one then 24.95 plus one more with a 30 percent off so 30percent off of 24.95 is 17.465 plus 24.95 is 42.415
You have to plug in the given numbers and perform each operation. Let me know if you have questions. The answers are circled.
I think it's a rational number.
Answer:
Equation: 5w = c
Step-by-step explanation:
k is a constant of proprtionality
» Therefore, equation becomes:
