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Semenov [28]
3 years ago
5

the solutions to a quadratic question are -6 ans +6. You figure it the original equation and write it in standard form ax2+bx+c=

0. What is the value of "b"?
Mathematics
1 answer:
Butoxors [25]3 years ago
8 0

Answer:

this must be (x+6)(x-6)

when that is multiplied out you get x^{2} + 36

so there would be no b, b therefore is equal to zero in this equation

Step-by-step explanation:

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What is the range of the relation below?
Greeley [361]
[6, -infinity)

have a good night
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3 years ago
Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul
IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: P(k) = \frac{\lambda^ke^{-k}}{k!} where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and \lambda = 7 into the formula:

P(k=7) = \frac{7^7e^{-7}}{7!}

P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

P(k\leq2) = P(k=0)+P(k=1)+P(k=2)

P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}

P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}

P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%

4 0
3 years ago
Lisa works part time at the cookie jar. She earns $4.25 an hour. Last week she worked from 6 p.m to 9 p.m on monday, tuesday, an
Marianna [84]

Answer:

38.25

Step-by-step explanation:

4.25x9

5 0
3 years ago
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Vikki [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which number is irrational? A. 3/8 B. 56/8 to the fourth C. 36 to the fourth over 4 to the fourth D. 0.19 repeating
mixer [17]
I believe that none would be irrational; an irrational number can't have terminating or repeating decimals. 3/8= .375, (56/8)^4=7^4=2,401, 36^4/4^4=6561, and .19 repeating is a repeating decimal. 
4 0
4 years ago
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