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WINSTONCH [101]
3 years ago
13

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

e other base. What are the lengths of the bases? Complete the explanation of how you found your answer.
One base is __ inches for one of the bases and __ inches for the other base.


Use the formula for the area of a trapezoid. Substitute 72 for A and 6 for h and simplify the equation to find __ = (b1 + b2). Use guess and check to find two numbers that add to __ with one number 6 more than the other to get __ inches for one of the bases and __ inches for the other base.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

A=\frac{1}{2} (b_{1} +b_{2} )h

where, h be the height of the trapezoid

b_{1} be the shorter base

b_{2} be the longer base

As per the given problem,

b_{2}=b_{1}  +6

Now,

Putting, A=72, b_{2}=b_{1}+6 and h=6 we get,

\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72

or, b_{1}+b_{1}+6 = \frac{(72)(2)}{6}

or, 2b_{1}+6 = 24

or, 2b_{1}=24-6

or, b_{1}= \frac{18}{2}

or, b_{1}=9

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

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