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neonofarm [45]
3 years ago
6

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

ical researcher selects a random sample of 1,000 adults and finds (by other means) that 4% have this type of cancer. Each of the 1,000 adults is given the new test, and it is found that the test indicates cancer in 99% of those who have it and in 1% of those who do not.
a) Based on these results, what is the probability of a randomly chosen person having cancer given that the test indicates cancer?
b) What is the probability of a person having cancer given that the test does not indicate cancer?

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test -  No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is  \frac{0.0396}{0.0396+0.0096}= \frac{33}{41}

The probability of someone picked at random has cancer given that test result indicates no cancer is \frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}

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How much larger is 6 times 10 to the 5th power compared to 2 times 10 to the 3rd power
lora16 [44]

Answer:

Either <em><u>10 times</u></em> or <u><em>598,000.</em></u>

Step-by-step explanation:

6 x 10 ^ 5 = 600,000

2 x 10 ^ 3 = 2,000

If we are figuring out the exact number, 600,000 - 2,000.  If we are finding out how many powers larger, count.

600,000 - 2,000 = 598,000

600,000 is 10 times larger than 2,000.

See?

600,0<u>00</u>

2,000

6 0
2 years ago
If f(x) = 7 + 4x and g(x)=1/2x, what is the value of (f/g)(5)?
Anestetic [448]
f(x)=7+4x;\ g(x)=\dfrac{1}{2}x\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}=\dfrac{7+4x}{\frac{1}{2}x}=\dfrac{2(7+4x)}{x}=\dfrac{14+8x}{x}\\\\\left(\dfrac{f}{g}\right)(5)=\dfrac{f(5)}{g(5)}=\dfrac{14+8\cdot5}{5}=\dfrac{14+40}{5}=\dfrac{54}{5}=10.8
8 0
2 years ago
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Which graph best represents the equation 2x + 4y equals negative 8
Hitman42 [59]
You have to solve for y
Subtract 2x to the other side
Divide both sides by 4
y=-1x/2-2
Graph D has a slope of -1/2 and a y-intercept of -2
6 0
3 years ago
What is the length of side AB with endpointsA(–5, 3) and B(4, 3)? units
QveST [7]

Answer:

9 units

Step-by-step explanation:

the y value doesnt change, so the distance from -5 to 4 is 9 units

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
2 years ago
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