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SVETLANKA909090 [29]

2 years ago

12

In a basket ball game, the Golden State Warriors make a total of 21 shots. Some shots were 2 points and some were 3 points. The

Warriors score a total of 50 points. How many 2-point shots and 3-point shots did they make?

1 answer:

Zarrin [17]2 years ago

3 0

8 3-point shots and 13 2-point shots.

8x3 = 24, 13x2 = 26,
24+26= 50.
13+ 8 = 21

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JulijaS [17]

Answer:

19.53

Step-by-step explanation:

First let's find the new price of the backpack:

40% of 29.99 is

29.99 * 0.40 = 11.99

So the new price of the backpack is

29.99 - 11.99 = 18.00

Now let's find the price with tax

8.5% of 18.00 is

18.00 * 0.085 = 1.53

So the cost of the backpack is

18.00 + 1.53 = $19.53

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britney has a secret number.if you subtract her numberfrom 16,the aswer is the same when you substract 4 from 12.what is britney

Nina [5.8K]

Britnes's secret number is 24

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3 years ago

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Hey there!<br><br> Can you help me please ? Thanks!

Vinil7 [7]

A. (140x110)+[(50x70)/2] = 15,400+1750= 17,150cm^2

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3 years ago

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Ashley and Gabby bought lunch from the food trucks on Sugar Day. Ashley bought 3 tacos and a drink for $7. Gabby bought 2 drinks

kramer

Answer:

$1.5

Step-by-step explanation:

This would be solved using a simultaneous equation

let tacos = t

drink = d

3t + d = 7 -- eqn 1

2t + 2d = 8 -- eqn 2

Multiply equation 1 by 2 to derive equation 3

6t + 2d = 14 eqn 3

Substract equation 2 from equation 3

6t + 2d = 14 -- eqn 3

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2t + 2d = 8 -- eqn 2

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solve for t

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= $1.5

8 0

3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago