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3 years ago

The doctor order 100mg of Rocephin. Available is 1g/1mL. How many mL is to be administered?

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Answer:

0.1 ML

Step-by-step explanation:

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Does anyone understand this

Nataliya [291]

For this problem, 0.25 in = 50 m. So

11 in = (11 in) • (50/0.25 m/in) = 2200 m

Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.

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3 years ago

I dont know how to answer this question please help me

qwelly [4]

Plot the points that it has for you and then figure out how many spaces it moved that will tell you your dialation

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4 years ago

Write the first 10 multiplies of 6 and 8 pairs of numbers and find this LCM

Gekata [30.6K]

↪ $\huge\rm{answer: } \: \boxed{ \purple{24 }}$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

M(6)= {0, 6, 12, 18, <u>24</u>, 30, 36, 42, 48, 54, 60 ...}

M(8) = {0, 8, 16, <u>24</u>, 32, 40, 48, 56, 64, 72, 80...}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

I hope you understood!✏

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

$\huge\boxed{ \boxed{ \rm{Hope \: this \: helps }}}$

7 0

3 years ago

Read 2 more answers

The sum of the circumference of two circles is 38π cm and the sum of their areas is 193π cm². Calculate the radii of the circles

sdas [7]

Answer:

The radii of the circles are 12 cm and 7cm.

Step-by-step explanation:

Let the radii of the circles be $r_{1}\ and\ r_{2}$

Given:

Sum of circumference of two circles= 38π cm

Formula for circumference of a circle with radius r = 2πr

$2\pi r_{1}+2\pi r_{2}=38\pi \\r_{1}+r_{2}=19$ ------------1

Sum of areas of two circles= 193π cm²

Area of circle with radius r = πr²

$\pi r_{1}^{2}+\pi r_{2}^{2}=193\pi \\r_{1}^{2}+r_{2}^{2}=193$ -------2

Substituting r2 = 19 - r1 in equation 2 we get:

$r_{1}^{2}+(19-r_{1})^{2}=193\\2r_{1}^{2}-38r_{1}+168=0\\r_{1}^{2}-19r_{1}+84=0\\(r_{1}-12)(r_{1}-7)=0\\r_{1}=12\ or\ 7$

Then r2 = 19 - r1

$r_{2}=12\ or\ 7$

7 0

3 years ago

Please please help me

Gala2k [10]

Answer:

89.0°

Step-by-step explanation:

The segment from the centre of the circle to the chord is a perpendicular bisector, hence

third side of right triangle = 12.7 ÷ 2 = 6.35

The angle subtended at the centre by arc CD is twice the angle subtended by the right triangle at the centre

The triangle from the centre to C is congruent to the triangle from the centre to D

Calculate the angle (Θ ) in the right triangle using the sine ratio

sinΘ = $\frac{opposite}{hypotenuse}$ = $\frac{6.35}{9.06}$

Θ = $sin^{-1}$ ( $\frac{6.35}{9.06}$ ) ≈ 44.5°

Hence

measure of CD = 2 × Θ = 2 × 44.5 = 89.0°

5 0

4 years ago