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Effectus [21]
3 years ago
7

How many ways can the letters of "collge" be arranged​

Mathematics
2 answers:
ELEN [110]3 years ago
6 0

COLLEGE is a 7 letter word.

here E and L will appear for two times so we will get denominator (2!*2!)

so,COLLEGE can be arranged in 7!/(1!*1!*2!*2!*1!)=1260

It is difficult to calculate the case when vowels don't come together so we will be going to calculate the opposite case when vowels do come together.

CLLG(OEE) =4+1 consider OEE as one letteer.

when vowels come together =(5!/2!)*(3!/2!)=180 (3!/2! is the arrangement of vowels total 3 vowels 3! and E repeats two times.)

vowels don't come together =1260-180=1080.

Hope this helps

salantis [7]3 years ago
4 0

Answer:

COLLEGE is a 7 letter word.

here E and L will appear for two times so we will get denominator (2!*2!)

so,COLLEGE can be arranged in 7!/(1!*1!*2!*2!*1!)=1260

It is difficult to calculate the case when vowels don't come together so we will be going to calculate the opposite case when vowels do come together.

CLLG(OEE) =4+1 consider OEE as one letteer.

when vowels come together =(5!/2!)*(3!/2!)=180 (3!/2! is the arrangement of vowels total 3 vowels 3! and E repeats two times.)

vowels don't come together =1260-180=1080.

Step-by-step explanation:

hope this helps <3 <3 <3 Aaliyah

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1 1/3 x 5/8 A.3/4 B.4/5 C.5/6 D.5/8​
dmitriy555 [2]

Answer:

c.5/6

Step-by-step explanation:

1 1/3 x 5/8  = 4/3 x  5/8

first multiply both numerator and d enumerator

then we get

20/ 24

divide both numerator and  d enumerator with 4

simplify that

=5/6

5 0
3 years ago
Show how to use known facts to find 6 x 9. Explain how you chose the facts you did
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8 0
3 years ago
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How many times would a face card (jack, queen, or king) likely be drawn from the deck in 260 draws?
Tanzania [10]

Answer:

8/10

Step-by-step explanation:

You would divide the cards and so you will get your answer

6 0
3 years ago
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Roopesh has $24 dollars to spend on a birthday gift. The store where he is shopping has a sale offering $5 off the regular price
Natasha2012 [34]

Answer:

r ≤ 29, r-5

The sale price can be compared with the regular price, r-5 ≤ 24

Step-by-step explanation:

Amount to spend = $24

Regular price = r

Sale = $5

Sale Price = r-5

The regular price will be $5, at the max, more than the amount Roopesh has to spend.

The sale price will be $24 or less than that for Roopesh to afford.

Inequality for regular price:

r-5 ≤ 24

r ≤ 29

So, the product Roopesh can afford is $29 or less than that.

What is the unknown? r ≤ 29

Following expression can represent the sale price:

Sale price = r-5  

The sale price can be compared with the regular price with the following:

Inequality representing the situation: r-5 ≤ 24

3 0
3 years ago
Two children, Ferdinand and Isabella, are playing with a water hose on a sunny summer day. Isabella is holding the hose in her h
wolverine [178]

Answer:

 f = 0.84 or 84%

Step-by-step explanation:

Given:

- Original constant velocity of water v_o = 3.5 m/s

- The original diameter of the hose opening d_o = 1.5 cm

- The total vertical distance y(f) = 1.0 m

- The total range x(f) = 10.0 m

Find:

What fraction of the original area does Isabella has to reduce or pinch so the water can cover the entire range.

Solution:

- We will assume the flow of water as a stream of particles that follow a path of single point.

- Using second kinematic equation in the vertical direction and compute the time it takes the water to reach the ground:

                                  y(t) = y(0) + v_y*t + 0.5*gt^2

Where, y(0) = v_y = 0,

                                  1.0 = 0.5*g*t^2

                                  t = sqrt ( 2*1 / 9.81 )

                                  t = 0.4515 s

- Now we will use the second equation of motion for the x- direction motion:

                                 x(t) = x(0) + v_x*t

Where, x(0) = 0,

                                 10 = 0 + v_x*(0.4515)

                                 v_x = 10 / 0.4515 = 22.1 m/s

- We have calculated the minimum velocity required to reach the range from isabella and ferdinand.

- We will use the continuity equation to compute the area required for the velocity calculated v_x = 22.1 m/s:

                                A_f*v_x = A_o*v_o

                                A_f = A_o*v_o / v_x

                                A_f = pi*0.015^2*3.5 / 4*22.1

                                A_f = 1.12 * 10^-4 m^2

- The fraction f of the reduction of area is:

                                f = (A_o - A_f) / A_o

                                f = (7.068*10^-8 - 1.12*10^-4) / (7.068*10^-8)

                               f = 0.84 or 84%

4 0
3 years ago
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