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Lynna [10]
3 years ago
9

How to figure out 2.73+0.003+0.158

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0
Fun! 

Line Up the decimals like a vertical addition problem.

Answer: 2.89100
Mademuasel [1]3 years ago
5 0
Line all of the answers up and you will get 2.891

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For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3
ale4655 [162]

Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) \frac{y^2 - 1}{y}  + \frac{y}{y - 3}

So the fractions are defined such that the denominator is never zero.

For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

Then the fractions exist for all real values except for y = 0 or y = 3

we can write this as:

R / {0} U { 3}

(the set of all real numbers except the elements 0 and 3)

2) \frac{b + 4}{b^2 + 7}

Let's see the values of b such that the denominator is zero:

b^2 + 7 = 0

b^2 = -7

b = √-7

This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.

The allowed values are R, the set of all real numbers.

3) \frac{a}{a*(a - 1) - 1}

Again, we need to find the value of a such that the denominator is zero.

a*(a - 1) - 1 = a^2 - a - 1

So we need to solve:

a^2 - a - 1 = 0

We can use the Bhaskara's formula, the two values of a are given by:

a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)}  }{2*1}  = \frac{1 \pm \sqrt{5} }{2}

Then the two values of a that are not allowed are:

a = (1 + √5)/2

a = (1 - √5)/2

Then the allowed values of a are:

R / {(1 + √5)/2} U {(1 - √5)/2}

7 0
2 years ago
If x=8 and y=14. Find y when x=48​
Sladkaya [172]

Answer:

Step-by-step explanation:

In picture shown.

6 0
3 years ago
There are approximately Pi times 10,000,000 seconds in one ____?
MissTica

The number of seconds in a year are 31,557,600 seconds, which gives;

There are approximately Pi times 10,000,000 seconds in one <u>year</u>.

<u />

<h3>How can the given statement be completed?</h3>

The number of seconds in one day = 86,400

The number of seconds in one week = 604,800

The number of seconds in a year = 31,557,600

Therefore;

\mathbf{\dfrac{The \ number  \ of  \ seconds  \ in \  a \  year}{10,000,000}}  = 3.1557600 \ which  \ is \ close \ to \3.14159 \approx \pi

Which gives;

The number of seconds in a year ≈ π × 10,000,000

The completed statement is therefore;

  • There are approximately Pi times 10,000,000 seconds in one <u>year</u>

Learn more about conversion of units here:

brainly.com/question/599249

7 0
2 years ago
Read 2 more answers
A line passes through the point (-7,5) And has a slope of 1/2 which is another point that the line passes through
Licemer1 [7]

(9,13) would be another point that the line passes through.

5 0
3 years ago
Read 2 more answers
When constructing a prependicular bisector why must the compass opening be greater than 1/2 the length of the segment ?
Tomtit [17]

Because otherwise the two circles you build wouldn't have any intersection!

You have to draw two circles, centered at the endpoints of the segment, and connect their intersection.

If the radii are less than half the length of the circle, the circles will have no interserction.

5 0
3 years ago
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