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velikii [3]
3 years ago
14

3k^2=11+6k : complete the square

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

3(k - 1)² = 12

Step-by-step explanation:

To complete the square, write the equation standard form and make the a term's coefficient 1.

3k² = 11 + 6k

3k² - 6k - 11 = 0

3(k² - 2k) = 11

Take the middle term -2k and divide the coefficient in 2 and square it. Here it is -2/2 = -1. -1² = 1. Add 1 to both sides.

3(k² - 2k + 1) = 11 + 1

3(k - 1)² = 12

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