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GREYUIT [131]
3 years ago
11

Matti built a greenhouse in his backyard as shown below

Mathematics
2 answers:
Vanyuwa [196]3 years ago
4 0

well, Matti's house is a triangular prism, and to get the volume of it, we simply get the area of the triangle upfront and multiply by its length of 15.

\bf \stackrel{\stackrel{\textit{area of }}{\textit{triangular front}}}{\cfrac{1}{2}(7)(7)}\times \stackrel{\textit{length}}{15}\implies \cfrac{49}{2}\cdot 15\implies 367.5~ft^3

Studentka2010 [4]3 years ago
4 0

Answer:

Option B.

Step-by-step explanation:

Volume of a green house in the backyard which in the shape of triangular prism V = (Area of base)×(Height)

In the figure attached,

Height of the triangular base = 7 ft

Base = 7 ft

Area of the triangle = \frac{1}{2}(7)(7)

Area = \frac{49}{2}=24.5 ft²

Therefore, volume of the prism = 24.5 × 15

                                                    = 367.5 ft²

Option B. is the correct option.

         

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Answer:

9/14 ; 18/23 ; 8/15

Step-by-step explanation:

7/21 = 1/3

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Answer:

  (x, y, z) = (7, 9, 90)

Step-by-step explanation:

The two acute angles between l1 and l2 are vertical, so congruent.

  (9x -7) = 8x

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ASAP 30 + Brainliest <br><br> Please only solve 2 - 5
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<u>QUESTION 2a</u>


We want to find the area of the given right angle triangle.


We use the formula

Area=\frac{1}{2}\times base\times height

The height of the triangle is =a cm.

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We substitute the given values to obtain,


Area=\frac{1}{2}\times 12\times a cm^2.

This simplifies to get an expression for the area to be

Area=6a cm^2.





<u>QUESTION 2b</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


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We substitute the values to obtain the area to be


Area=7 \times y


The expression for the area is

Area=7y


<u>QUESTION 2c.</u>


The given diagram is a rectangle.


The area of a rectangle is given by the formula

Area=length \times width


The length of the rectangle is l=2x cm and the width of the rectangle is w=4 cm.


We substitute the values to obtain the area to be


Area=2x \times 4


The expression for the area is

Area=8x


<u>QUESTION 2d</u>


The given diagram is a square.

The area of a square is given by,

Area=l^2.


where l=b m is the length of one side.


The expression for the area is

Area=b^2 m^2


<u>QUESTION 2e</u>

The given diagram is an isosceles triangle.


The area of this triangle can be found using the formula,

Area=\frac{1}{2}\times base\times height.

The height of the triangle is 4cm.


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The expression for the area is

Area=\frac{1}{2}\times 6a \times 4cm^2


Area=12a cm^2


<u>QUESTION 3a</u>

Perimeter is the distance around the figure.

Let P be the perimeter, then

P=x+x+x+x

The expression for the perimeter is

P=4x mm


<u>QUESTION 3b</u>

The given figure is a rectangle.


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P=L+B+L+B


This simplifies to

P=2L+2B

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P=2(L+B)


<u>QUESTION 3c</u>

The given figure is a parallelogram.

Perimeter is the distance around the parallelogram

Perimeter=3q+P+3q+P

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<u>QUESTION 3d</u>

The given figure is a rhombus.

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The given figure is an equilateral triangle.

The perimeter is the distance around this triangle.

Let P be the perimeter, then,

P=2x+2x+2x


We simplify to get,


P=6x mm


QUESTION 3f

The figure is an isosceles triangle so two sides are equal.


We add all the distance around the triangle to find the perimeter.


This implies that,


Perimeter=3m+5m+5m


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P=m+2m+n+n-3+3-1

We simplify to get,

P=3m+2n-1mm


QUESTION 3i

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We add all the distance around the figure to obtain the perimeter.

Let P be the perimeter.


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We regroup the terms to get,

P=2a+a+a-b+2b+2b

This will simplify to give us the expression for the perimeter to be

P=4a+3bmm.


QUESTION 4a

The given figure is a square.


The area of a square is given by the formula;

Area=l^2

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Area=(2m)^2


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The given figure is a rectangle.


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We substitute the values into the formula to get,

Area =3p \times p

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Area =3p^2 cm^2




See attachment for the continuation


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3 years ago
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