Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
I think 2401...I just asked Siri
£480
2:3:7 = 2+3+7 = 12
2
--- 0f £480 = £80
12
3
--- of £480 = £120
12
7
--- of £480 = £280
12
answer = £80 : £120 : £280
Well 344 rounded to the nearest hundred is 300 so times 24 its 7,200 add 4 is 7,204 but take away 12 is 7,192 and there's your answer
Answer:
Step-by-step explanation:
First, remember that the maximum degree of an angle totals 360°.
Since we already have 294°, this means that what is left must total 
.
Therefore, this means that our two smaller angles must equal 66°. So:
Solve for x. Add on the left:
Subtract 8 from both sides. Therefore, the value of x is:
